If x and y are positive integers such that x=8y+12,what is the greatest common divisor of x and 1) x=12u,where u is an integer2) y=12z,where z is 由题知:x=4(2y+3)由(1)知:x=12u 则y=3k k is an integer.x=12(2k+1) 则x,y最大公因子不能确定.
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![If x and y are positive integers such that x=8y+12,what is the greatest common divisor of x and 1) x=12u,where u is an integer2) y=12z,where z is 由题知:x=4(2y+3)由(1)知:x=12u 则y=3k k is an integer.x=12(2k+1) 则x,y最大公因子不能确定.](/uploads/image/z/9706845-21-5.jpg?t=If+x+and+y+are+positive+integers+such+that+x%3D8y%2B12%2Cwhat+is+the+greatest+common+divisor+of+x+and+1%29+x%3D12u%2Cwhere+u+is+an+integer2%29+y%3D12z%2Cwhere+z+is+%E7%94%B1%E9%A2%98%E7%9F%A5%3Ax%3D4%282y%2B3%29%E7%94%B1%281%29%E7%9F%A5%3Ax%3D12u+%E5%88%99y%3D3k+k+is+an+integer.x%3D12%282k%2B1%29+%E5%88%99x%2Cy%E6%9C%80%E5%A4%A7%E5%85%AC%E5%9B%A0%E5%AD%90%E4%B8%8D%E8%83%BD%E7%A1%AE%E5%AE%9A.)
If x and y are positive integers such that x=8y+12,what is the greatest common divisor of x and 1) x=12u,where u is an integer2) y=12z,where z is 由题知:x=4(2y+3)由(1)知:x=12u 则y=3k k is an integer.x=12(2k+1) 则x,y最大公因子不能确定.
If x and y are positive integers such that x=8y+12,what is the greatest common divisor of x and
1) x=12u,where u is an integer
2) y=12z,where z is 由题知:x=4(2y+3)
由(1)知:x=12u 则y=3k k is an integer.x=12(2k+1) 则x,y最大公因子不能确定.
由(2)知:y=12z 则x=12(6z+1) ,因此x,y的公因子是12.这个题的1 为什么最大公因子不能确定呢?2 为什么就可以呢?
If x and y are positive integers such that x=8y+12,what is the greatest common divisor of x and 1) x=12u,where u is an integer2) y=12z,where z is 由题知:x=4(2y+3)由(1)知:x=12u 则y=3k k is an integer.x=12(2k+1) 则x,y最大公因子不能确定.
1)
x=12u=4(2y+3),=> Y=3/2(u-1),
X=12u,=> Y/X=u-1/8u,(你看u=3带入x,y.公约为3,=5,公约为6.)
x,y正整数
=>公约不定.
2)
同上理:Y/x=8Z+1/Z 无论z是几,公约都只是1
gmat的题吗,