[k(k+1)/12](3k^2+11k+10)+(k+1)(k+2) 怎么化简结果是[(k+1)(k+2)/12][3(k+1)^2+11(k+1)+10] 不过我不知到详细的步骤
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/28 17:34:06
![[k(k+1)/12](3k^2+11k+10)+(k+1)(k+2) 怎么化简结果是[(k+1)(k+2)/12][3(k+1)^2+11(k+1)+10] 不过我不知到详细的步骤](/uploads/image/z/9326317-13-7.jpg?t=%5Bk%28k%2B1%29%2F12%5D%283k%5E2%2B11k%2B10%29%2B%28k%2B1%29%28k%2B2%29+%E6%80%8E%E4%B9%88%E5%8C%96%E7%AE%80%E7%BB%93%E6%9E%9C%E6%98%AF%5B%28k%2B1%29%28k%2B2%29%2F12%5D%5B3%28k%2B1%29%5E2%2B11%28k%2B1%29%2B10%5D+%E4%B8%8D%E8%BF%87%E6%88%91%E4%B8%8D%E7%9F%A5%E5%88%B0%E8%AF%A6%E7%BB%86%E7%9A%84%E6%AD%A5%E9%AA%A4)
[k(k+1)/12](3k^2+11k+10)+(k+1)(k+2) 怎么化简结果是[(k+1)(k+2)/12][3(k+1)^2+11(k+1)+10] 不过我不知到详细的步骤
[k(k+1)/12](3k^2+11k+10)+(k+1)(k+2) 怎么化简
结果是[(k+1)(k+2)/12][3(k+1)^2+11(k+1)+10] 不过我不知到详细的步骤
[k(k+1)/12](3k^2+11k+10)+(k+1)(k+2) 怎么化简结果是[(k+1)(k+2)/12][3(k+1)^2+11(k+1)+10] 不过我不知到详细的步骤
3k^2+11k+10
=(3k+5)(k+2)
[k(k+1)/12](3k^2+11k+10)+(k+1)(k+2)
=[k(k+1)/12](3k+5)(k+2)+(k+1)(k+2)
=(k+1)(k+2)[k(3k+5)/12+1]
=(k+1)(k+2)[k(3k+5)+12]/12
=(k+1)(k+2)(3k^2+5k+1)/12
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[k(k+1)/12](3k^2+11k+10)+(k+1)(k+2) 怎么化简结果是[(k+1)(k+2)/12][3(k+1)^2+11(k+1)+10] 不过我不知到详细的步骤
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