试用消元法解下列方程组:详细解释下{ X1-x2+x3-x4=0 2x1-x2+3x3-2x4=-1 3x1-2x2-x3+2x4=4
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![试用消元法解下列方程组:详细解释下{ X1-x2+x3-x4=0 2x1-x2+3x3-2x4=-1 3x1-2x2-x3+2x4=4](/uploads/image/z/8880320-56-0.jpg?t=%E8%AF%95%E7%94%A8%E6%B6%88%E5%85%83%E6%B3%95%E8%A7%A3%E4%B8%8B%E5%88%97%E6%96%B9%E7%A8%8B%E7%BB%84%EF%BC%9A%E8%AF%A6%E7%BB%86%E8%A7%A3%E9%87%8A%E4%B8%8B%7B+X1-x2%2Bx3-x4%3D0+++++++++++++++2x1-x2%2B3x3-2x4%3D-1+++++++++++++++3x1-2x2-x3%2B2x4%3D4)
试用消元法解下列方程组:详细解释下{ X1-x2+x3-x4=0 2x1-x2+3x3-2x4=-1 3x1-2x2-x3+2x4=4
试用消元法解下列方程组:详细解释下
{ X1-x2+x3-x4=0
2x1-x2+3x3-2x4=-1
3x1-2x2-x3+2x4=4
试用消元法解下列方程组:详细解释下{ X1-x2+x3-x4=0 2x1-x2+3x3-2x4=-1 3x1-2x2-x3+2x4=4
我给你做出来了,我是用数学编辑器做的,花了我好长时间,