求几道物质的电离方程式1.KCLO32.Ca(HCO3)23.HCLO4.Cu(OH)25.(NH4)2CO36.NAHS7.NH4HSO3
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![求几道物质的电离方程式1.KCLO32.Ca(HCO3)23.HCLO4.Cu(OH)25.(NH4)2CO36.NAHS7.NH4HSO3](/uploads/image/z/8157162-66-2.jpg?t=%E6%B1%82%E5%87%A0%E9%81%93%E7%89%A9%E8%B4%A8%E7%9A%84%E7%94%B5%E7%A6%BB%E6%96%B9%E7%A8%8B%E5%BC%8F1.KCLO32.Ca%28HCO3%2923.HCLO4.Cu%28OH%2925.%28NH4%292CO36.NAHS7.NH4HSO3)
求几道物质的电离方程式1.KCLO32.Ca(HCO3)23.HCLO4.Cu(OH)25.(NH4)2CO36.NAHS7.NH4HSO3
求几道物质的电离方程式
1.KCLO3
2.Ca(HCO3)2
3.HCLO
4.Cu(OH)2
5.(NH4)2CO3
6.NAHS
7.NH4HSO3
求几道物质的电离方程式1.KCLO32.Ca(HCO3)23.HCLO4.Cu(OH)25.(NH4)2CO36.NAHS7.NH4HSO3
1.KCLO3 = K+ + CLO3-
2.Ca(HCO3)2 = Ca2+ + 2HCO3-
3.HCLO H+ + CLO-
4.Cu(OH)2 = Cu2+ + 2OH-
5.(NH4)2CO3 = 2NH4+ + CO32-
6.NAHS = NA+ + HS-
7.NH4HSO3 = NH4+ + HSO3-
KCLO3==K(+)+ClO3(-)
Ca(HCO3)2==Ca(2+)+2HCO3(-)
HClO<==>H(+)+ClO(-)
Cu(OH)2<==>(熔融)Cu(2+)+2OH(-)
(NH4)2CO3==2NH4(+)+CO3(2-)
NaHS==Na(+)+HS(-)
NH4HSO3==NH4(+)+HSO3(-)
1)KClO3 == [K]+ + [ClO3]-
2)Ca(HCO3)2 == [Ca]2+ + 2[HCO3]-
[HCO3]- =可逆= [H]+ + [CO3]2-
3)HClO =可逆= [H]+ + [ClO]-
4)Cu(OH)2 =可逆= [Cu]2+ + 2[OH]-
5)(NH4)2CO3 == 2[NH4]+ + [CO3]2-
全部展开
1)KClO3 == [K]+ + [ClO3]-
2)Ca(HCO3)2 == [Ca]2+ + 2[HCO3]-
[HCO3]- =可逆= [H]+ + [CO3]2-
3)HClO =可逆= [H]+ + [ClO]-
4)Cu(OH)2 =可逆= [Cu]2+ + 2[OH]-
5)(NH4)2CO3 == 2[NH4]+ + [CO3]2-
6)NaHS == [Na]+ + [HS]-
[HS]- =可逆= [H]+ + [S]2-
7)NH4HSO3 == [NH4]+ + [HSO3]-
[HSO3]- =可逆= [H]+ + [SO3]2-
氢氧化铜不可能熔融,其在100℃以下就会分解为CuO和H2O。
收起
.KCLO3 = K+ + CLO3-
2.Ca(HCO3)2 = Ca2+ + 2HCO3-
3.HCLO <—> H+ + CLO-
4.Cu(OH)2 <—> Cu2+ + 2OH-
5.(NH4)2CO3 = 2NH4+ + CO3...
全部展开
.KCLO3 = K+ + CLO3-
2.Ca(HCO3)2 = Ca2+ + 2HCO3-
3.HCLO <—> H+ + CLO-
4.Cu(OH)2 <—> Cu2+ + 2OH-
5.(NH4)2CO3 = 2NH4+ + CO32-
6.NAHS = NA+ + HS-
HS-<—>H+ +S2-
7.NH4HSO3 = NH4+ + HSO3-
HSO3-<—>H+ +SO3-
收起