若x、y满足2x+y=6,x-3y=1,求7y(x-3y)²-2(3y-x)³的值
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![若x、y满足2x+y=6,x-3y=1,求7y(x-3y)²-2(3y-x)³的值](/uploads/image/z/759895-7-5.jpg?t=%E8%8B%A5x%E3%80%81y%E6%BB%A1%E8%B6%B32x%2By%3D6%2Cx-3y%3D1%2C%E6%B1%827y%28x-3y%29%26%23178%3B-2%283y-x%29%26%23179%3B%E7%9A%84%E5%80%BC)
若x、y满足2x+y=6,x-3y=1,求7y(x-3y)²-2(3y-x)³的值
若x、y满足2x+y=6,x-3y=1,求7y(x-3y)²-2(3y-x)³的值
若x、y满足2x+y=6,x-3y=1,求7y(x-3y)²-2(3y-x)³的值
7y(x-3y)²-2(3y-x)³=7y(x-3y)²+2(x-3y)³=(x-3y)²[7y+2(x-3y)=(x-3y)²(7y+2X-6y)
=(x-3y)²(2x+y)
因为 2x+y=6,x-3y=1
所以 原式=1²*6=6
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