200分求一道数学题,最好能教下这种题目应该怎么求,求懂英文的高手Change the rectangular coordinates to polar coordinates with r > 0 and 0 ≤ θ ≤ 2派 (Enter your answers as ordered pairs.) (a) (−1,−1)(r,θ) = (
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![200分求一道数学题,最好能教下这种题目应该怎么求,求懂英文的高手Change the rectangular coordinates to polar coordinates with r > 0 and 0 ≤ θ ≤ 2派 (Enter your answers as ordered pairs.) (a) (−1,−1)(r,θ) = (](/uploads/image/z/7007049-9-9.jpg?t=200%E5%88%86%E6%B1%82%E4%B8%80%E9%81%93%E6%95%B0%E5%AD%A6%E9%A2%98%2C%E6%9C%80%E5%A5%BD%E8%83%BD%E6%95%99%E4%B8%8B%E8%BF%99%E7%A7%8D%E9%A2%98%E7%9B%AE%E5%BA%94%E8%AF%A5%E6%80%8E%E4%B9%88%E6%B1%82%2C%E6%B1%82%E6%87%82%E8%8B%B1%E6%96%87%E7%9A%84%E9%AB%98%E6%89%8BChange+the+rectangular+coordinates+to+polar+coordinates+with+r+%3E+0+and+0+%E2%89%A4+%CE%B8+%E2%89%A4+2%E6%B4%BE+%28Enter+your+answers+as+ordered+pairs.%29+%28a%29+%28%26%238722%3B1%2C%26%238722%3B1%29%28r%2C%CE%B8%29+%3D+%28)
200分求一道数学题,最好能教下这种题目应该怎么求,求懂英文的高手Change the rectangular coordinates to polar coordinates with r > 0 and 0 ≤ θ ≤ 2派 (Enter your answers as ordered pairs.) (a) (−1,−1)(r,θ) = (
200分求一道数学题,最好能教下这种题目应该怎么求,求懂英文的高手
Change the rectangular coordinates to polar coordinates with r > 0 and 0 ≤ θ ≤ 2派 (Enter your answers as ordered pairs.)
(a)
(−1,−1)
(r,θ) =
(b)
(−根号3,−1)
(r,θ) =
200分求一道数学题,最好能教下这种题目应该怎么求,求懂英文的高手Change the rectangular coordinates to polar coordinates with r > 0 and 0 ≤ θ ≤ 2派 (Enter your answers as ordered pairs.) (a) (−1,−1)(r,θ) = (
直角坐标和极坐标转换
直角坐标系中的点和原点的连线为r,该线与x轴正向夹角为θ
(a)(r,θ) = (√2,5π/4)
(b)(r,θ) =(2,7π/6)
(a)
(−1, −1)
r= √2
θ = 5π/4
(b)
(−√3, −1)
r = √(3+1) =2
θ = π +π/6 = 7π/6
rectangular coordinates :直角坐标
polar coordinates :极坐标
(-1,-1)= 根号2,5π/4
(−根号3, −1)=2,7π/6
直角坐标转化为极坐标 在直角坐标系中 先根据坐标确定点的位置 点与O点的连线与 x正半轴的夹角就是极坐标的角
(-1,-1)的模为√2 r = √2 θ = 5/4π
同理另外个r = 2 θ =7/6 π
这是个直角坐标到极坐标的转换问题:
(a) r= √2
θ = 5π/4
(b) r = √(3+1) =2
θ = π +π/6 = 7π/6
就是r=√x²+y² (比如第一题就是 √((-1)²+ (-1)² )
θ 的公式如下:
x=ρcosθ y=ρsinθ ,由上述二公式...
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这是个直角坐标到极坐标的转换问题:
(a) r= √2
θ = 5π/4
(b) r = √(3+1) =2
θ = π +π/6 = 7π/6
就是r=√x²+y² (比如第一题就是 √((-1)²+ (-1)² )
θ 的公式如下:
x=ρcosθ y=ρsinθ ,由上述二公式,可得到从直角坐标系中x和 y两坐标如何计算出极坐标下的坐标
θ=arctany/x ( x不等于0)
其中,在 x≠0的情况下:若 y为正数 θ= 90° (π/2 radians);若 y为负,则 θ= 270° (3π/2 radians).
收起
将直角坐标换为极坐标
a:r*cos(θ)=x=-1;r*sin(θ)=y=-1∴r=sqrt(2),θ=1.25π∴(r,θ)=(sqrt(2),1.25π)
b:r*cos(θ)=x=-sqrt(3);r*sin(θ)=y=-1∴r=2,θ=7/6*π∴(r,θ)=(2,7/6*π)
(sqrt=根号)
直角坐标系转换为极坐标系,要求r > 0 and 0 ≤ θ ≤ 2π;
关系为: x = r*cos(θ),
y = r*sin(θ),
(a) (−1, −1),x^2+y^2=r^2=2;那么r=√2,θ为5π/4;
(b) (−√3, −1),x^2+y^2=r^2=4;那么r=2,θ为7π/6;