若x,y,z满足3x+7x+z=1,4x+10y+z=2006,求分式2005x+2005y+2005z/x+3y的值
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![若x,y,z满足3x+7x+z=1,4x+10y+z=2006,求分式2005x+2005y+2005z/x+3y的值](/uploads/image/z/6890140-28-0.jpg?t=%E8%8B%A5x%2Cy%2Cz%E6%BB%A1%E8%B6%B33x%2B7x%2Bz%3D1%2C4x%2B10y%2Bz%3D2006%2C%E6%B1%82%E5%88%86%E5%BC%8F2005x%2B2005y%2B2005z%2Fx%2B3y%E7%9A%84%E5%80%BC)
若x,y,z满足3x+7x+z=1,4x+10y+z=2006,求分式2005x+2005y+2005z/x+3y的值
若x,y,z满足3x+7x+z=1,4x+10y+z=2006,求分式2005x+2005y+2005z/x+3y的值
若x,y,z满足3x+7x+z=1,4x+10y+z=2006,求分式2005x+2005y+2005z/x+3y的值
3x+7x+z=1 ①
4x+10y+z=2006 ②
②-①得
x+3y=2005 ③
①乘以3得
9x+21y+3z=3 ④
②乘以2得
8x+20y+2z=4012 ⑤
④-⑤得
x+y+z=-4009
所以所求式子
=2005(x+y+z)/(x+3y)
=2005*(-4009)/2005
=-4009
用4x+10y+z=2006减去3x+7y+z=1
得x+3y=2005
用3x+7y+z=1乘以3得9x+21y+3z=3-----P
用4x+10y+z=2006乘以2得8x+20y+2z=4012-----Q
用方程P减去方程Q得x+y+z=-4009
所以所求式子为(2005*4009)/(-2005)=-4009
明教为您解答,
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用4x+10y+z=2006减去3x+7y+z=1
得x+3y=2005
用3x+7y+z=1乘以3得9x+21y+3z=3-----P
用4x+10y+z=2006乘以2得8x+20y+2z=4012-----Q
用方程P减去方程Q得x+y+z=-4009
所以所求式子为(2005*4009)/(-2005)=-4009
明教为您解答,
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题目3x+7x+z=1?没错?