设函数f(x)=4^x/4^x+2,那么f(1/11)+f(2/11)+……+f(10/11)的值为?具体计算步骤
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/30 05:59:03
![设函数f(x)=4^x/4^x+2,那么f(1/11)+f(2/11)+……+f(10/11)的值为?具体计算步骤](/uploads/image/z/6856685-53-5.jpg?t=%E8%AE%BE%E5%87%BD%E6%95%B0f%28x%29%3D4%5Ex%2F4%5Ex%2B2%2C%E9%82%A3%E4%B9%88f%281%2F11%29%2Bf%282%2F11%29%2B%E2%80%A6%E2%80%A6%2Bf%2810%2F11%29%E7%9A%84%E5%80%BC%E4%B8%BA%3F%E5%85%B7%E4%BD%93%E8%AE%A1%E7%AE%97%E6%AD%A5%E9%AA%A4)
设函数f(x)=4^x/4^x+2,那么f(1/11)+f(2/11)+……+f(10/11)的值为?具体计算步骤
设函数f(x)=4^x/4^x+2,那么f(1/11)+f(2/11)+……+f(10/11)的值为?具体计算步骤
设函数f(x)=4^x/4^x+2,那么f(1/11)+f(2/11)+……+f(10/11)的值为?具体计算步骤
设函数f(x)=4^x/(4^x+2)
则f(x)+f(1-x)=4^x/(4^x+2)+4^(1-x)/[4^(1-x)+2]
=4^x/(4^x+1)+4/(4+2*4^x]
=4^x/(4^x+2)+2/(4^x+2)
=(4^x+2)/(4^x+2)
=1 (注意:f(x)+f(1-x)=1 其中x+1-x=1)
所以f(1/11)+f(2/11)+……+f(10/11)
=[f(1/11)+f(10/11)]+[f(2/11)+f(9/11)]+...+[f(5/11)+f(6/11)]
=1+1+1+1+1
=5
前一位仁兄有些笔误,我给纠正一下:则则f(x)+f(1-x)=4^x/(4^x+2)+4^(1-x)/[4^(1-x)+2]
=4^x/(4^x+1)+4/(4+2*4^x应改为(x)+f(1-x)=4^x/(4^x+2)+4^(...
全部展开
前一位仁兄有些笔误,我给纠正一下:则则f(x)+f(1-x)=4^x/(4^x+2)+4^(1-x)/[4^(1-x)+2]
=4^x/(4^x+1)+4/(4+2*4^x应改为(x)+f(1-x)=4^x/(4^x+2)+4^(1-x)/[4^(1-x)+2]
=4^x/(4^x+2)+4/(4+2*4^x]
虽然只是小错误,把考试实属不允许犯错的,可不能因小失大
收起