求高数大师帮我解一题极限题...
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/02 07:26:47
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求高数大师帮我解一题极限题...
求高数大师帮我解一题极限题...
求高数大师帮我解一题极限题...
原式=limx→0 (x^2-sin^2x)/(x^2*sin^2x)
=limx→0 (x^2-sin^2x)/x^4 (sinx~x,替换)
=limx→0 (2x-2sinxcosx)/4x^3,
=limx→0 (2x-sin2x)/4x^3,
=limx→0 (2-2cos2x)/12x^2,
=limx→0 (1-cos2x)/6x^2,
=limx→0 2sin2x/12x,
=limx→0 4cos2x/12,
=1/3.