SAT数学题概率题求解答If n and p are to be selected at random from sets N and P respectively,what is the probability the n/(2p) will be a member of set 求讲解解题思路N {12,18,2,6}P {1,4,2,3}
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![SAT数学题概率题求解答If n and p are to be selected at random from sets N and P respectively,what is the probability the n/(2p) will be a member of set 求讲解解题思路N {12,18,2,6}P {1,4,2,3}](/uploads/image/z/511228-28-8.jpg?t=SAT%E6%95%B0%E5%AD%A6%E9%A2%98%E6%A6%82%E7%8E%87%E9%A2%98%E6%B1%82%E8%A7%A3%E7%AD%94If+n+and+p+are+to+be+selected+at+random+from+sets+N+and+P+respectively%2Cwhat+is+the+probability+the+n%2F%282p%29+will+be+a+member+of+set+%E6%B1%82%E8%AE%B2%E8%A7%A3%E8%A7%A3%E9%A2%98%E6%80%9D%E8%B7%AFN+%7B12%2C18%2C2%2C6%7DP+%7B1%2C4%2C2%2C3%7D)
SAT数学题概率题求解答If n and p are to be selected at random from sets N and P respectively,what is the probability the n/(2p) will be a member of set 求讲解解题思路N {12,18,2,6}P {1,4,2,3}
SAT数学题概率题求解答
If n and p are to be selected at random from sets N and P respectively,what is the probability the n/(2p) will be a member of set
求讲解解题思路
N {12,18,2,6}
P {1,4,2,3}
SAT数学题概率题求解答If n and p are to be selected at random from sets N and P respectively,what is the probability the n/(2p) will be a member of set 求讲解解题思路N {12,18,2,6}P {1,4,2,3}
因为数量很少,我觉得想不出高明的方法也可以用笨方法:
1、看看每一个n除以2p能得到几个属于P的结果:12有2个(除以2*2和2*3),18有1个(除以2*3),2有1个(除以2*1),6有2个(除以2*1和2*3),加起来一共6个.
2、排列组合n/(2p)可以有多少种结果:每个n对应4个2p,共16个.
3、所以几率是6/16=3/8
那道工资题我不会,好像条件不全.因为看到这道题放了一天没人做,所以把笨方法写出来供你参考.