5.6*(l1^2 + 25)^(1/2) + 6*((l1 - 15)^2 + l2^2)^(1/2) + 27.7*((l2 - 18)^2 + 25)^(1/2)0
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![5.6*(l1^2 + 25)^(1/2) + 6*((l1 - 15)^2 + l2^2)^(1/2) + 27.7*((l2 - 18)^2 + 25)^(1/2)0](/uploads/image/z/4330342-46-2.jpg?t=5.6%2A%28l1%5E2+%2B+25%29%5E%281%2F2%29+%2B+6%2A%28%28l1+-+15%29%5E2+%2B+l2%5E2%29%5E%281%2F2%29+%2B+27.7%2A%28%28l2+-+18%29%5E2+%2B+25%29%5E%281%2F2%290)
5.6*(l1^2 + 25)^(1/2) + 6*((l1 - 15)^2 + l2^2)^(1/2) + 27.7*((l2 - 18)^2 + 25)^(1/2)0
5.6*(l1^2 + 25)^(1/2) + 6*((l1 - 15)^2 + l2^2)^(1/2) + 27.7*((l2 - 18)^2 + 25)^(1/2)
0
5.6*(l1^2 + 25)^(1/2) + 6*((l1 - 15)^2 + l2^2)^(1/2) + 27.7*((l2 - 18)^2 + 25)^(1/2)0
5.6*(l1^2 + 25)^(1/2) + 6*((l1 - 15)^2 + l2^2)^(1/2) + 27.7*((l2 - 18)^2 + 25)^(1/2)
0
Objective value: 425.649672872956330
l1 = 6.36028483414693
l2 = 8.
在lingo中直接输入
model:
min=5.6*(l1^2 + 25)^(1/2) + 6*((l1 - 15)^2 + l2^2)^(1/2) + 27.7*((l2 - 18)^2 + 25)^(1/2);
l1<=15;
l1>=0;
l2<=8;
l2>=0;
end谢谢 !的结果是?是否和一楼的一样呀!另外,lingo中的根...
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在lingo中直接输入
model:
min=5.6*(l1^2 + 25)^(1/2) + 6*((l1 - 15)^2 + l2^2)^(1/2) + 27.7*((l2 - 18)^2 + 25)^(1/2);
l1<=15;
l1>=0;
l2<=8;
l2>=0;
end
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