计算数列极限,当N趋向于无穷时,根号下(N^2+4N+5)-(N-1)的极限
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计算数列极限,当N趋向于无穷时,根号下(N^2+4N+5)-(N-1)的极限
计算数列极限,当N趋向于无穷时,根号下(N^2+4N+5)-(N-1)的极限
计算数列极限,当N趋向于无穷时,根号下(N^2+4N+5)-(N-1)的极限
√(n^2+4n+5)-(n-1)
=[(n^2+4n+5)-(n-1)^2]/[√(n^2+4n+5)+(n-1)]
=(6n+6)/[√(n^2+4n+5)+(n-1)]
=(6+6/n)/[√(1+4/n+5/n^2)+(1-1/n)]
所以,极限是(6+0)/[√(1+0+0)+(1-0)]=3
是前面有根号而已还是前部都在根号下面?
计算数列极限,当N趋向于无穷时,根号下(N^2+4N+5)-(N-1)的极限
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