已知tan2θ=3/4(π/2<θ<π),求(2cos^2θ/2+sinθ+10/[√2cos(θ+π/4]
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已知tan2θ=3/4(π/2<θ<π),求(2cos^2θ/2+sinθ+10/[√2cos(θ+π/4]
已知tan2θ=3/4(π/2<θ<π),求(2cos^2θ/2+sinθ+10/[√2cos(θ+π/4]
已知tan2θ=3/4(π/2<θ<π),求(2cos^2θ/2+sinθ+10/[√2cos(θ+π/4]
π/2<θ<π,则π<θ<2π,而tan2θ=3/4>0,则π<θ<3π/2,从而π/2<θ<3π/4.得:sin2θ=-3/5,cos2θ=-4/5=2cos²θ-1=1-2sin²θ,则cosθ=-√10/10,sinθ=3√10/10,代入计算:
原式=[sinθ+11+cosθ]/[sinθ-cosθ]=……
已知tan2θ=3/4(π/2
已知tan2θ=3/4(π/2
已知tan2θ=3/4(π/2<θ<π),求(2cos^2θ/2+sinθ+10/[√2cos(θ+π/4]
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