已知x.y满足(x-y+2>=0.x+y-4>=0.2x-y-5<=0),求Z=[x+2y-4]的最大值……补充:[]为绝对值符号…
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![已知x.y满足(x-y+2>=0.x+y-4>=0.2x-y-5<=0),求Z=[x+2y-4]的最大值……补充:[]为绝对值符号…](/uploads/image/z/2486412-36-2.jpg?t=%E5%B7%B2%E7%9F%A5x.y%E6%BB%A1%E8%B6%B3%EF%BC%88x-y%2B2%EF%BC%9E%EF%BC%9D0.x%2By-4%EF%BC%9E%EF%BC%9D0.2x-y-5%EF%BC%9C%EF%BC%9D0%EF%BC%89%2C%E6%B1%82Z%3D%5Bx%2B2y-4%5D%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC%E2%80%A6%E2%80%A6%E8%A1%A5%E5%85%85%EF%BC%9A%5B%5D%E4%B8%BA%E7%BB%9D%E5%AF%B9%E5%80%BC%E7%AC%A6%E5%8F%B7%E2%80%A6)
已知x.y满足(x-y+2>=0.x+y-4>=0.2x-y-5<=0),求Z=[x+2y-4]的最大值……补充:[]为绝对值符号…
已知x.y满足(x-y+2>=0.x+y-4>=0.2x-y-5<=0),求Z=[x+2y-4]的最大值……补充:[]为绝对值符号…
已知x.y满足(x-y+2>=0.x+y-4>=0.2x-y-5<=0),求Z=[x+2y-4]的最大值……补充:[]为绝对值符号…
根据不等式组,可以求得 7≥x≥1,9≥y≥3
所以25≥x+2y≥7
所以,Z的最大值=21
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