=[1/(log2 3)+lg2 3]²-[1/(log2 3)]²-(log2 3)²=2*(1/log2 3)*log2 3,怎么转的啊
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=[1/(log2 3)+lg2 3]²-[1/(log2 3)]²-(log2 3)²=2*(1/log2 3)*log2 3,怎么转的啊
=[1/(log2 3)+lg2 3]²-[1/(log2 3)]²-(log2 3)²=2*(1/log2 3)*log2 3,怎么转的啊
=[1/(log2 3)+lg2 3]²-[1/(log2 3)]²-(log2 3)²=2*(1/log2 3)*log2 3,怎么转的啊
[1/(log2 3)+lg2 3]²=[1/(log2 3)]²+(log2 3)²+2*1/(log2 3)*lg2 3=[1/(log2 3)]²+(log2 3)²+2
又因为(1/log2 3)*log2 3=1
那么左边就有[1/(log2 3)+lg2 3]²-[1/(log2 3)]²-(log2 3)²=[1/(log2 3)]²+(log2 3)²+2-[1/(log2 3)]²-(log2 3)²=2
右边有2*(1/log2 3)*log2 3=2*1=2
即:左边等于右边
LOG2(3)*LG2=?急求!
=[1/(log2 3)+lg2 3]²-[1/(log2 3)]²-(log2 3)²=2*(1/log2 3)*log2 3,怎么转的啊
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