设f(x)=(x-2^n+1)ln(x-2^n+1)-x(n属于n+),求证f(x)>=3sn+/6sn-2
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![设f(x)=(x-2^n+1)ln(x-2^n+1)-x(n属于n+),求证f(x)>=3sn+/6sn-2](/uploads/image/z/11502127-55-7.jpg?t=%E8%AE%BEf%28x%29%3D%28x-2%5En%2B1%29ln%28x-2%5En%2B1%29-x%28n%E5%B1%9E%E4%BA%8En%2B%29%2C%E6%B1%82%E8%AF%81f%28x%29%3E%3D3sn%2B%2F6sn-2)
设f(x)=(x-2^n+1)ln(x-2^n+1)-x(n属于n+),求证f(x)>=3sn+/6sn-2
设f(x)=(x-2^n+1)ln(x-2^n+1)-x(n属于n+),求证f(x)>=3sn+
/6sn-2
设f(x)=(x-2^n+1)ln(x-2^n+1)-x(n属于n+),求证f(x)>=3sn+/6sn-2
参考例题:
答案:
设f(x)=(x^2)ln(1+x),求f(0)的n阶导数.n大于等于3.
设f(x)=(x-2^n+1)ln(x-2^n+1)-x(n属于n+),求证f(x)>=3sn+/6sn-2
设f(x)=(x-2^n+1)ln(x-2^n+1)-x(n属于n+),求证f(x)>=3sn+/6sn-2
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