如何得出:2+sin2x+cos2x=根号2sinsin(2x+π/4)+2还有如何得到:sin(x+π/6)+sin(x-π/6)+cosx=2sinxcosπ/6+cosx.....
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![如何得出:2+sin2x+cos2x=根号2sinsin(2x+π/4)+2还有如何得到:sin(x+π/6)+sin(x-π/6)+cosx=2sinxcosπ/6+cosx.....](/uploads/image/z/11458597-13-7.jpg?t=%E5%A6%82%E4%BD%95%E5%BE%97%E5%87%BA%EF%BC%9A2%2Bsin2x%2Bcos2x%3D%E6%A0%B9%E5%8F%B72sinsin%282x%2B%CF%80%2F4%29%2B2%E8%BF%98%E6%9C%89%E5%A6%82%E4%BD%95%E5%BE%97%E5%88%B0%EF%BC%9Asin%28x%2B%CF%80%2F6%29%2Bsin%28x-%CF%80%2F6%29%2Bcosx%3D2sinxcos%CF%80%2F6%2Bcosx.....)
如何得出:2+sin2x+cos2x=根号2sinsin(2x+π/4)+2还有如何得到:sin(x+π/6)+sin(x-π/6)+cosx=2sinxcosπ/6+cosx.....
如何得出:2+sin2x+cos2x=根号2sinsin(2x+π/4)+2
还有如何得到:sin(x+π/6)+sin(x-π/6)+cosx=2sinxcosπ/6+cosx.....
如何得出:2+sin2x+cos2x=根号2sinsin(2x+π/4)+2还有如何得到:sin(x+π/6)+sin(x-π/6)+cosx=2sinxcosπ/6+cosx.....
1.你最后结果写错了.2+sin2x+cos2x=2+根号2(根号2/2*sin2x+根号2/2*cos2x)
=2+根号2(cosπ/4*sin2x+sinπ/4*cos2x)
=2+根号2*sin(2x+π/4)
2.用和差化积公式(在网上可以搜到)
sin(x+π/6)+sin(x-π/6)+cosx
=2sin【(x+π/6)/2+(x-π/6)/2】cos【(x+π/6)/2-(x-π/6)/2】+cosx
=2sinxcosπ/6+cosx
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如何得出:2+sin2x+cos2x=根号2sinsin(2x+π/4)+2还有如何得到:sin(x+π/6)+sin(x-π/6)+cosx=2sinxcosπ/6+cosx.....
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