八题快百度问问
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八题快百度问问
八题快百度问问
八题快百度问问
x²-4x+4+|y-1|=0
(x-2)²+|y-1|=0
x-2=0,y-1=0
x=2,y=1
(x/y-y/x)÷(x+y)
=(2-1/2)÷3
=1/2
答:x^2-4x+4与|y-1|互为相反数,相反数的和为0:
x^2-4x+4+|y-1|=0
(x-2)^2+|y-1|=0
根据平方数和绝对值的非负性质有:
x-2=0
y-1=0
解得:x=2,y=1
所以:
(x/y-y/x)/(x+y)
=(x^2-y^2)/[xy(x+y)]
=(x-y)/(xy)
=1/y-1/x
=1-1/2
=1/2
x=2,y=1,结果0.5