求一道英文数学题的答案If the position of a particle at a time is given by the equation x(t)=2t^3-9t^2+12t-18Find the distance(距离非位移)of the particle from t=0 to t=4.
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/30 00:25:45
![求一道英文数学题的答案If the position of a particle at a time is given by the equation x(t)=2t^3-9t^2+12t-18Find the distance(距离非位移)of the particle from t=0 to t=4.](/uploads/image/z/1036756-28-6.jpg?t=%E6%B1%82%E4%B8%80%E9%81%93%E8%8B%B1%E6%96%87%E6%95%B0%E5%AD%A6%E9%A2%98%E7%9A%84%E7%AD%94%E6%A1%88If+the+position+of+a+particle+at+a+time+is+given+by+the+equation+x%28t%29%3D2t%5E3-9t%5E2%2B12t-18Find+the+distance%28%E8%B7%9D%E7%A6%BB%E9%9D%9E%E4%BD%8D%E7%A7%BB%EF%BC%89of+the+particle+from+t%3D0+to+t%3D4.)
求一道英文数学题的答案If the position of a particle at a time is given by the equation x(t)=2t^3-9t^2+12t-18Find the distance(距离非位移)of the particle from t=0 to t=4.
求一道英文数学题的答案
If the position of a particle at a time is given by the equation x(t)=2t^3-9t^2+12t-18
Find the distance(距离非位移)of the particle from t=0 to t=4.
求一道英文数学题的答案If the position of a particle at a time is given by the equation x(t)=2t^3-9t^2+12t-18Find the distance(距离非位移)of the particle from t=0 to t=4.
对x(t)求导,得到6t^2-18t+12,令这个式子等于0,则有x=1或者2,即x(t)在这两点处取得极值;再根据单调性大致得出波形,
x(0)= -18;x(1)= -13;x(2)= -14;x(4)= 14;
由波形知距离=|x(1) - x(0)| + |x (2) - x(1)| + |x(4) - x(2)| =34
(方法肯定是对的,结果你自己再算下,应该没有错)
求两点(0,-18),(4,14)间距离,结果是4*65½,四倍的六十五开平方
x(t)=2t^3-9t^2+12t-18
x(0)=-18
x(4)=2*4^3-9*4^2+12*4-18=14
x(4)-x(0)=32