(1)分解因式:(x+1)(x+2)(x+3)-x(x+1)(x+2) (2)计算:1×2+2×3+3×4+.+n(n+1)(n为正整数)(3)1*2*3+2*3*4+4*5*6+ …+24*25*26,并说明算法
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/05 16:18:56
![(1)分解因式:(x+1)(x+2)(x+3)-x(x+1)(x+2) (2)计算:1×2+2×3+3×4+.+n(n+1)(n为正整数)(3)1*2*3+2*3*4+4*5*6+ …+24*25*26,并说明算法](/uploads/image/z/9792854-62-4.jpg?t=%281%29%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F%EF%BC%9A%28x%2B1%29%28x%2B2%29%28x%2B3%29-x%28x%2B1%29%28x%2B2%29+%282%29%E8%AE%A1%E7%AE%97%EF%BC%9A1%C3%972%2B2%C3%973%2B3%C3%974%2B.%2Bn%EF%BC%88n%2B1%29%28n%E4%B8%BA%E6%AD%A3%E6%95%B4%E6%95%B0%EF%BC%89%EF%BC%883%EF%BC%891%2A2%2A3%2B2%2A3%2A4%2B4%2A5%2A6%2B+%E2%80%A6%2B24%2A25%2A26%2C%E5%B9%B6%E8%AF%B4%E6%98%8E%E7%AE%97%E6%B3%95)
(1)分解因式:(x+1)(x+2)(x+3)-x(x+1)(x+2) (2)计算:1×2+2×3+3×4+.+n(n+1)(n为正整数)(3)1*2*3+2*3*4+4*5*6+ …+24*25*26,并说明算法
(1)分解因式:(x+1)(x+2)(x+3)-x(x+1)(x+2) (2)计算:1×2+2×3+3×4+.+n(n+1)(n为正整数)
(3)1*2*3+2*3*4+4*5*6+ …+24*25*26,并说明算法
(1)分解因式:(x+1)(x+2)(x+3)-x(x+1)(x+2) (2)计算:1×2+2×3+3×4+.+n(n+1)(n为正整数)(3)1*2*3+2*3*4+4*5*6+ …+24*25*26,并说明算法
(1)分解因式:(x+1)(x+2)(x+3)-x(x+1)(x+2)
(x+1)(x+2)(x+3)-x(x+1)(x+2)
=(x+1)(x+2)[(x+3)-x]
=3(x+1)(x+2)
(2)计算:1×2+2×3+3×4+……+n(n+1)(n为正整数)
由于n(n+1)=[n(n+1)(n+2)-(n-1)n(n+1)]/3
所以1*2+2*3+……+n(n+1)
=[1*2*3-0+2*3*4-1*2*3+…….+n(n+1)(n+2)-(n-1)n(n+1)]/3
[前后消项]
=[n(n+1)(n+2)]/3
(3)1*2*3+2*3*4+3*4*5+……+24*25*26,并说明算法
因为4(n-1)n(n+1)=(n-1)n(n+1)(n+2)-(n-2)(n-1)n(n+1)
所以
1*2*3+2*3*4+3*4*5+……+n(n+1)(n+2)
=n(n+1)(n+2)(n+3)/4
1*2*3+2*3*4+3*4*5+.+24*25*26
=24*25*26*27/4
=105300
1)
(x+1)(x+2)(x+3)-x(x+1)(x+2) =(x+1)(x+2)[(x+3)-x]= 3(x+1)(x+2)
2)
1×2+2×3+3×4+。。。+n(n+1)=1+2^2+3^2+...+n^2+1+2+...+n
=n(n+1)(2n+1)/6+n(n+1)/2
=n(n+1)[(2n+1)/6+1/2]
=n(n+1)(3n+2/3)
=n(n+1)(9n+2)/3