已知x/2=y/3=z/4,xyz不等于0,求x+3y-2z/2x+y的值
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![已知x/2=y/3=z/4,xyz不等于0,求x+3y-2z/2x+y的值](/uploads/image/z/976843-19-3.jpg?t=%E5%B7%B2%E7%9F%A5x%2F2%3Dy%2F3%3Dz%2F4%2Cxyz%E4%B8%8D%E7%AD%89%E4%BA%8E0%2C%E6%B1%82x%2B3y-2z%2F2x%2By%E7%9A%84%E5%80%BC)
已知x/2=y/3=z/4,xyz不等于0,求x+3y-2z/2x+y的值
已知x/2=y/3=z/4,xyz不等于0,求x+3y-2z/2x+y的值
已知x/2=y/3=z/4,xyz不等于0,求x+3y-2z/2x+y的值
令x/2=y/3=z/4=k
所以x=2k,y=3k,z=4k
带入要求解的式子,消去k得 原式等于3/7
即结果是3/7