如何解(m+1)(m-1)(m²-1)?(x-2y+3z)²等于几?
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/04 07:36:16
![如何解(m+1)(m-1)(m²-1)?(x-2y+3z)²等于几?](/uploads/image/z/8794692-36-2.jpg?t=%E5%A6%82%E4%BD%95%E8%A7%A3%28m%2B1%29%28m-1%29%28m%26%23178%3B-1%EF%BC%89%3F%EF%BC%88x-2y%2B3z%EF%BC%89%26%23178%3B%E7%AD%89%E4%BA%8E%E5%87%A0%EF%BC%9F)
如何解(m+1)(m-1)(m²-1)?(x-2y+3z)²等于几?
如何解(m+1)(m-1)(m²-1)?
(x-2y+3z)²等于几?
如何解(m+1)(m-1)(m²-1)?(x-2y+3z)²等于几?
(m+1)(m-1)(m²-1)
=(m²-1)(m²-1)
=(m²-1)²
希望能帮到您,
(m+1)(m-1)(m²-1)
= (m²-1)(m²-1)
= (m²-1)²
是要解这个式子=0么?
原式=(m+1)(m-1)(m^2-1)
=(m+1)(m-1)(m+1)(m-1)
=(m+1)^2(m-1)^2
=0
两个式子都是平方
所以=0的条件是 m+1=0 或 m-1=0
那么 m=-1或m=1
记得采纳哟亲