微积分的三个问题已知lim φ(x)=a,lim f(u)=f(a),试证明lim f[φ(x)]=f(a)=f[lim φ(x)]x→x0 u→a x→x0 x→x0 lim [(1-x)^1/2 - 3]/[2+x^1/3]=x→-∞ 已知lim (1+1/x)^x=e,则lim (1+1/x)^x=e,请证明x→+∞ x→-∞ 悬赏分提高到顶
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![微积分的三个问题已知lim φ(x)=a,lim f(u)=f(a),试证明lim f[φ(x)]=f(a)=f[lim φ(x)]x→x0 u→a x→x0 x→x0 lim [(1-x)^1/2 - 3]/[2+x^1/3]=x→-∞ 已知lim (1+1/x)^x=e,则lim (1+1/x)^x=e,请证明x→+∞ x→-∞ 悬赏分提高到顶](/uploads/image/z/8753231-47-1.jpg?t=%E5%BE%AE%E7%A7%AF%E5%88%86%E7%9A%84%E4%B8%89%E4%B8%AA%E9%97%AE%E9%A2%98%E5%B7%B2%E7%9F%A5lim+%CF%86%28x%29%3Da%2Clim+f%28u%29%3Df%28a%29%2C%E8%AF%95%E8%AF%81%E6%98%8Elim+f%5B%CF%86%28x%29%5D%3Df%28a%29%3Df%5Blim+%CF%86%28x%29%5Dx%E2%86%92x0+u%E2%86%92a+x%E2%86%92x0+x%E2%86%92x0+lim+%5B%281-x%29%5E1%2F2+-+3%5D%2F%5B2%2Bx%5E1%2F3%5D%3Dx%E2%86%92-%E2%88%9E+%E5%B7%B2%E7%9F%A5lim+%281%2B1%2Fx%29%5Ex%3De%2C%E5%88%99lim+%281%2B1%2Fx%29%5Ex%3De%2C%E8%AF%B7%E8%AF%81%E6%98%8Ex%E2%86%92%2B%E2%88%9E+x%E2%86%92-%E2%88%9E+%E6%82%AC%E8%B5%8F%E5%88%86%E6%8F%90%E9%AB%98%E5%88%B0%E9%A1%B6)
微积分的三个问题已知lim φ(x)=a,lim f(u)=f(a),试证明lim f[φ(x)]=f(a)=f[lim φ(x)]x→x0 u→a x→x0 x→x0 lim [(1-x)^1/2 - 3]/[2+x^1/3]=x→-∞ 已知lim (1+1/x)^x=e,则lim (1+1/x)^x=e,请证明x→+∞ x→-∞ 悬赏分提高到顶
微积分的三个问题
已知lim φ(x)=a,lim f(u)=f(a),试证明lim f[φ(x)]=f(a)=f[lim φ(x)]
x→x0 u→a x→x0 x→x0
lim [(1-x)^1/2 - 3]/[2+x^1/3]=
x→-∞
已知lim (1+1/x)^x=e,则lim (1+1/x)^x=e,请证明
x→+∞ x→-∞
悬赏分提高到顶了,
微积分的三个问题已知lim φ(x)=a,lim f(u)=f(a),试证明lim f[φ(x)]=f(a)=f[lim φ(x)]x→x0 u→a x→x0 x→x0 lim [(1-x)^1/2 - 3]/[2+x^1/3]=x→-∞ 已知lim (1+1/x)^x=e,则lim (1+1/x)^x=e,请证明x→+∞ x→-∞ 悬赏分提高到顶
1.
任意给出一个正数ε,由lim f(u)=f(a)( u→a )可知,必存在η>0,使得0
三个题,打字都打到手酸,你给15分?