两道初二分式数学题 急!1.a²-b²/a²b+ab²÷(1- ( a²+b²/2ab)) 其中a=2+根号3 b=2-根号32.((x²-3/x-1)-2)÷1/x-1 其中x满足x²-2x-3=0
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![两道初二分式数学题 急!1.a²-b²/a²b+ab²÷(1- ( a²+b²/2ab)) 其中a=2+根号3 b=2-根号32.((x²-3/x-1)-2)÷1/x-1 其中x满足x²-2x-3=0](/uploads/image/z/8695524-12-4.jpg?t=%E4%B8%A4%E9%81%93%E5%88%9D%E4%BA%8C%E5%88%86%E5%BC%8F%E6%95%B0%E5%AD%A6%E9%A2%98+%E6%80%A5%211.a%26%23178%3B-b%26%23178%3B%2Fa%26%23178%3Bb%2Bab%26%23178%3B%C3%B7%EF%BC%881-+%EF%BC%88+a%26%23178%3B%2Bb%26%23178%3B%2F2ab%EF%BC%89%EF%BC%89+++%E5%85%B6%E4%B8%ADa%3D2%2B%E6%A0%B9%E5%8F%B73++b%3D2-%E6%A0%B9%E5%8F%B732.%EF%BC%88%28x%26%23178%3B-3%2Fx-1%29-2%29%C3%B71%2Fx-1+++++++%E5%85%B6%E4%B8%ADx%E6%BB%A1%E8%B6%B3x%26%23178%3B-2x-3%3D0)
两道初二分式数学题 急!1.a²-b²/a²b+ab²÷(1- ( a²+b²/2ab)) 其中a=2+根号3 b=2-根号32.((x²-3/x-1)-2)÷1/x-1 其中x满足x²-2x-3=0
两道初二分式数学题 急!
1.a²-b²/a²b+ab²÷(1- ( a²+b²/2ab)) 其中a=2+根号3 b=2-根号3
2.((x²-3/x-1)-2)÷1/x-1 其中x满足x²-2x-3=0
两道初二分式数学题 急!1.a²-b²/a²b+ab²÷(1- ( a²+b²/2ab)) 其中a=2+根号3 b=2-根号32.((x²-3/x-1)-2)÷1/x-1 其中x满足x²-2x-3=0
1.a=2+根号3 b=2-根号3
a²-b²/a²b+ab²÷(1- ( a²+b²/2ab))
=[(a+b)(a-b)]/[ab(a+b)]÷[-(a-b)²/2ab]
=-[(a-b)/ab]×[2ab/(a-b)²]=-2/(a-b)
=-2/(2+√3-2+√3)=-1/√3=-√3/3
2..x满足x²-2x-3=0,
((x²-3/x-1)-2)÷1/x-1
=[(x²-3-2x+2)]/(x-1)÷1/(x-1)
= x²-2x-3+2 =2,