如图,在直角坐标系中,矩形ABCO的边OA在x轴上,边OC在y轴上,点B的坐标为(1,3),将矩形沿对角线AC翻折B点落在D点的位置,且AB交y轴于点,那么点D的坐标为A.(-4/5,12/5) B.(-2/5,13/5) C.(-1/2,13/5) D.(-3/5,12/5)
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/29 19:09:15
![如图,在直角坐标系中,矩形ABCO的边OA在x轴上,边OC在y轴上,点B的坐标为(1,3),将矩形沿对角线AC翻折B点落在D点的位置,且AB交y轴于点,那么点D的坐标为A.(-4/5,12/5) B.(-2/5,13/5) C.(-1/2,13/5) D.(-3/5,12/5)](/uploads/image/z/8664060-12-0.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E7%9B%B4%E8%A7%92%E5%9D%90%E6%A0%87%E7%B3%BB%E4%B8%AD%2C%E7%9F%A9%E5%BD%A2ABCO%E7%9A%84%E8%BE%B9OA%E5%9C%A8x%E8%BD%B4%E4%B8%8A%2C%E8%BE%B9OC%E5%9C%A8y%E8%BD%B4%E4%B8%8A%2C%E7%82%B9B%E7%9A%84%E5%9D%90%E6%A0%87%E4%B8%BA%EF%BC%881%2C3%EF%BC%89%2C%E5%B0%86%E7%9F%A9%E5%BD%A2%E6%B2%BF%E5%AF%B9%E8%A7%92%E7%BA%BFAC%E7%BF%BB%E6%8A%98B%E7%82%B9%E8%90%BD%E5%9C%A8D%E7%82%B9%E7%9A%84%E4%BD%8D%E7%BD%AE%2C%E4%B8%94AB%E4%BA%A4y%E8%BD%B4%E4%BA%8E%E7%82%B9%2C%E9%82%A3%E4%B9%88%E7%82%B9D%E7%9A%84%E5%9D%90%E6%A0%87%E4%B8%BAA.%28-4%2F5%2C12%2F5%29+B.%28-2%2F5%2C13%2F5%29+C.%28-1%2F2%2C13%2F5%29+D.%28-3%2F5%2C12%2F5%29)
如图,在直角坐标系中,矩形ABCO的边OA在x轴上,边OC在y轴上,点B的坐标为(1,3),将矩形沿对角线AC翻折B点落在D点的位置,且AB交y轴于点,那么点D的坐标为A.(-4/5,12/5) B.(-2/5,13/5) C.(-1/2,13/5) D.(-3/5,12/5)
如图,在直角坐标系中,矩形ABCO的边OA在x轴上,边OC在y轴上,点B的坐标为(1,
3),将矩形沿对角线AC翻折B点落在D点的位置,且AB交y轴于点,那么点D的坐标为A.(-4/5,12/5) B.(-2/5,13/5) C.(-1/2,13/5) D.(-3/5,12/5)
如图,在直角坐标系中,矩形ABCO的边OA在x轴上,边OC在y轴上,点B的坐标为(1,3),将矩形沿对角线AC翻折B点落在D点的位置,且AB交y轴于点,那么点D的坐标为A.(-4/5,12/5) B.(-2/5,13/5) C.(-1/2,13/5) D.(-3/5,12/5)
选A. 过D作DF⊥AF于F, ∵点B的坐标为(1,3), ∴AO=1,AB=3, 根据折叠可知:CD=OA, 而∠D=∠AOE=90°,∠DEC=∠AEO, ∴△CDE≌△AOE, ∴OE=DE,OA=CD=1, 设OE=x,那么CE=3-x,DE=x, ∴在Rt△DCE中,CE2=DE2+CD2, ∴(3-x)2=x2+12, ∴x=4/3,又DF⊥AF, ∴DF∥EO, ∴△AEO∽△ADF,而AD=AB=3, ∴AE=CE=3-4/3=5/3, ∴AE:AD=EO;DF=:ao;af:, ∴DF=12/5,AF=9/5, ∴OF=4/5, ∴D的坐标为(.(-4/5,12/5)).故选A.