已知O为坐标原点,点M(-2,0),若N(x,y)满足不等式组 X大于等于1已知O为坐标原点,点M(-2,0),若N(x,y)满足不等式组 X大于等于1,Y大于等于0,X+Y小于等于4,则向量OM*ON的取值范围是,答案是【-8,1}不好
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![已知O为坐标原点,点M(-2,0),若N(x,y)满足不等式组 X大于等于1已知O为坐标原点,点M(-2,0),若N(x,y)满足不等式组 X大于等于1,Y大于等于0,X+Y小于等于4,则向量OM*ON的取值范围是,答案是【-8,1}不好](/uploads/image/z/8568918-54-8.jpg?t=%E5%B7%B2%E7%9F%A5O%E4%B8%BA%E5%9D%90%E6%A0%87%E5%8E%9F%E7%82%B9%2C%E7%82%B9M%EF%BC%88-2%2C0%EF%BC%89%2C%E8%8B%A5N%28x%2Cy%29%E6%BB%A1%E8%B6%B3%E4%B8%8D%E7%AD%89%E5%BC%8F%E7%BB%84+X%E5%A4%A7%E4%BA%8E%E7%AD%89%E4%BA%8E1%E5%B7%B2%E7%9F%A5O%E4%B8%BA%E5%9D%90%E6%A0%87%E5%8E%9F%E7%82%B9%2C%E7%82%B9M%EF%BC%88-2%2C0%EF%BC%89%2C%E8%8B%A5N%28x%2Cy%29%E6%BB%A1%E8%B6%B3%E4%B8%8D%E7%AD%89%E5%BC%8F%E7%BB%84++X%E5%A4%A7%E4%BA%8E%E7%AD%89%E4%BA%8E1%2CY%E5%A4%A7%E4%BA%8E%E7%AD%89%E4%BA%8E0%2CX%2BY%E5%B0%8F%E4%BA%8E%E7%AD%89%E4%BA%8E4%2C%E5%88%99%E5%90%91%E9%87%8FOM%2AON%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%E6%98%AF%2C%E7%AD%94%E6%A1%88%E6%98%AF%E3%80%90-8%2C1%7D%E4%B8%8D%E5%A5%BD)
已知O为坐标原点,点M(-2,0),若N(x,y)满足不等式组 X大于等于1已知O为坐标原点,点M(-2,0),若N(x,y)满足不等式组 X大于等于1,Y大于等于0,X+Y小于等于4,则向量OM*ON的取值范围是,答案是【-8,1}不好
已知O为坐标原点,点M(-2,0),若N(x,y)满足不等式组 X大于等于1
已知O为坐标原点,点M(-2,0),若N(x,y)满足不等式组 X大于等于1,Y大于等于0,X+Y小于等于4,则向量OM*ON的取值范围是,答案是【-8,1}
不好意思,点M是(-2,1)
已知O为坐标原点,点M(-2,0),若N(x,y)满足不等式组 X大于等于1已知O为坐标原点,点M(-2,0),若N(x,y)满足不等式组 X大于等于1,Y大于等于0,X+Y小于等于4,则向量OM*ON的取值范围是,答案是【-8,1}不好
OM*ON=-2x
因为 X大于等于1,Y大于等于0,X+Y小于等于4
所以 X大于等于1,小于等于4
所以 OM*ON=-2x 大于等于-8,小于等于-2
你是不是题目写错了.
向量OM*ON是复数
必须分别写出实部和虚部的取值范围
答案有问题
5开根号*10开根号小于等于OM*ON小于等于5开根号*4