已知α∈(-π,0),cosα=-1/3,则tanα等于 A.√2 B.2√2 C.3 D.3√2
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![已知α∈(-π,0),cosα=-1/3,则tanα等于 A.√2 B.2√2 C.3 D.3√2](/uploads/image/z/8539155-27-5.jpg?t=%E5%B7%B2%E7%9F%A5%CE%B1%E2%88%88%28-%CF%80%2C0%29%2Ccos%CE%B1%3D-1%2F3%2C%E5%88%99tan%CE%B1%E7%AD%89%E4%BA%8E+A.%E2%88%9A2+B.2%E2%88%9A2+C.3+D.3%E2%88%9A2)
已知α∈(-π,0),cosα=-1/3,则tanα等于 A.√2 B.2√2 C.3 D.3√2
已知α∈(-π,0),cosα=-1/3,则tanα等于 A.√2 B.2√2 C.3 D.3√2
已知α∈(-π,0),cosα=-1/3,则tanα等于 A.√2 B.2√2 C.3 D.3√2
由题意可知.sinα=-2√2/3 tanα=(sinα)/(cosα)=(-2√2/3)/(-1/3) = 2√2 选B