分式方程.换元法.(1+x)/(x²+2)+(x²+2)/2(1-x)=3/2.设(1-x)/(x²+2)=y.原分式方程是不是y+2/y=3/2(未化简)如不是请说明为什么?
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![分式方程.换元法.(1+x)/(x²+2)+(x²+2)/2(1-x)=3/2.设(1-x)/(x²+2)=y.原分式方程是不是y+2/y=3/2(未化简)如不是请说明为什么?](/uploads/image/z/7804281-57-1.jpg?t=%E5%88%86%E5%BC%8F%E6%96%B9%E7%A8%8B.%E6%8D%A2%E5%85%83%E6%B3%95.%281%2Bx%29%2F%28x%26%23178%3B%2B2%EF%BC%89%2B%EF%BC%88x%26%23178%3B%2B2%EF%BC%89%2F2%EF%BC%881-x%EF%BC%89%3D3%2F2.%E8%AE%BE%EF%BC%881-x%EF%BC%89%2F%EF%BC%88x%26%23178%3B%2B2%EF%BC%89%3Dy.%E5%8E%9F%E5%88%86%E5%BC%8F%E6%96%B9%E7%A8%8B%E6%98%AF%E4%B8%8D%E6%98%AFy%2B2%2Fy%3D3%2F2%EF%BC%88%E6%9C%AA%E5%8C%96%E7%AE%80%EF%BC%89%E5%A6%82%E4%B8%8D%E6%98%AF%E8%AF%B7%E8%AF%B4%E6%98%8E%E4%B8%BA%E4%BB%80%E4%B9%88%3F)
分式方程.换元法.(1+x)/(x²+2)+(x²+2)/2(1-x)=3/2.设(1-x)/(x²+2)=y.原分式方程是不是y+2/y=3/2(未化简)如不是请说明为什么?
分式方程.换元法.
(1+x)/(x²+2)+(x²+2)/2(1-x)=3/2.
设(1-x)/(x²+2)=y.
原分式方程是不是y+2/y=3/2(未化简)
如不是请说明为什么?
分式方程.换元法.(1+x)/(x²+2)+(x²+2)/2(1-x)=3/2.设(1-x)/(x²+2)=y.原分式方程是不是y+2/y=3/2(未化简)如不是请说明为什么?
不是
是y+1/(2y)=3/2
所以2y²-3y+1=0
y=1/2,y=1
(1-x)/(x²+2)=1/2
x=0,x=-2
(1-x)/(x²+2)=1
x=-1
所以
x=0,x=-2,x=-1
不是。
因为(1+x)/(x²+2)不是(x²+2)/(1-x)的倒数。