1.若sinQ-cosQ=2分之1,则cos^3Q-sin^3Q=2.化简:根号下1-sin²1190°=3.sin(-1200°)+cos6分之47π=4.sin70°×cos750°+sin(-690°)×cos(-660°)=5.sin6分之25π= tan690°=6.sin470°×cos750°+sin(-690°)×cos(-660°)=7.
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![1.若sinQ-cosQ=2分之1,则cos^3Q-sin^3Q=2.化简:根号下1-sin²1190°=3.sin(-1200°)+cos6分之47π=4.sin70°×cos750°+sin(-690°)×cos(-660°)=5.sin6分之25π= tan690°=6.sin470°×cos750°+sin(-690°)×cos(-660°)=7.](/uploads/image/z/7678311-15-1.jpg?t=1.%E8%8B%A5sinQ-cosQ%3D2%E5%88%86%E4%B9%8B1%2C%E5%88%99cos%5E3Q-sin%5E3Q%3D2.%E5%8C%96%E7%AE%80%EF%BC%9A%E6%A0%B9%E5%8F%B7%E4%B8%8B1-sin%26%23178%3B1190%C2%B0%3D3.sin%EF%BC%88-1200%C2%B0%EF%BC%89%2Bcos6%E5%88%86%E4%B9%8B47%CF%80%3D4.sin70%C2%B0%C3%97cos750%C2%B0%2Bsin%EF%BC%88-690%C2%B0%EF%BC%89%C3%97cos%EF%BC%88-660%C2%B0%EF%BC%89%3D5.sin6%E5%88%86%E4%B9%8B25%CF%80%3D+tan690%C2%B0%3D6.sin470%C2%B0%C3%97cos750%C2%B0%2Bsin%EF%BC%88-690%C2%B0%EF%BC%89%C3%97cos%EF%BC%88-660%C2%B0%EF%BC%89%3D7.)
1.若sinQ-cosQ=2分之1,则cos^3Q-sin^3Q=2.化简:根号下1-sin²1190°=3.sin(-1200°)+cos6分之47π=4.sin70°×cos750°+sin(-690°)×cos(-660°)=5.sin6分之25π= tan690°=6.sin470°×cos750°+sin(-690°)×cos(-660°)=7.
1.若sinQ-cosQ=2分之1,则cos^3Q-sin^3Q=
2.化简:根号下1-sin²1190°=
3.sin(-1200°)+cos6分之47π=
4.sin70°×cos750°+sin(-690°)×cos(-660°)=
5.sin6分之25π= tan690°=
6.sin470°×cos750°+sin(-690°)×cos(-660°)=
7.已知log2^x=3^y,则y分之x等于
8.若(4分之1)^(2a+1)<(4分之1)^(3-2a),则实数a的取值范围是
9.设a=log3^10,b=log3^7,则3^(a-b)=
10.已知log5【log3(log2^x)】=0,则x=
11..(log4^3+log8^3)(log3^2+log9^8)等于
12.函数f(x)=a^x(a>0且a≠1)在区间【1,2】上的最大值比最小值大2分之a,求a的值(要解题过程)
1.若sinQ-cosQ=2分之1,则cos^3Q-sin^3Q=2.化简:根号下1-sin²1190°=3.sin(-1200°)+cos6分之47π=4.sin70°×cos750°+sin(-690°)×cos(-660°)=5.sin6分之25π= tan690°=6.sin470°×cos750°+sin(-690°)×cos(-660°)=7.
1、11/16
2、cos70
3、0
4、sin100
5、1/2 -3分之根号3
6、1
7、(表述是否有问题)
8、a>1/2
9、10/7
10、8
11、25/12*log2^3
12、a分成两种情况来讨论大于1跟小于1
当a<1时,a-a^2=a/2得出a=1/2
当a>1时,a^2-a=a/2得出a=3/2
骚导航键萨丹哈空
太乱了
第一题是sinx=2tan(x/2)/1+tan^2(x/2)
cos=[1-tan^2(x/2)]/1+tan^2(x/2)
这俩带入求出tan(x/2)就可解了
你这出的题太多了
第二题没有步骤是+-cos110°
3,4,5,6不用做吧。。就是算
后面你要回求导就各种求导就能做,,太多了,不想写