(1)计算(-2)^1999+(-2)^2000等于( )(2)(5/8)^2004*(-1.6)^2005/(-1)^2003=( )(3)已知a1+a2=1,a2+a3=2,a3+a4=3,…,a99+a100=99,a100+a1=100,那么a1+a2+a3+…+a100=( )(4)若x^2+3x-1=0,则x^3+5x^2+5x+18=( )
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![(1)计算(-2)^1999+(-2)^2000等于( )(2)(5/8)^2004*(-1.6)^2005/(-1)^2003=( )(3)已知a1+a2=1,a2+a3=2,a3+a4=3,…,a99+a100=99,a100+a1=100,那么a1+a2+a3+…+a100=( )(4)若x^2+3x-1=0,则x^3+5x^2+5x+18=( )](/uploads/image/z/7657536-48-6.jpg?t=%EF%BC%881%EF%BC%89%E8%AE%A1%E7%AE%97%EF%BC%88-2%EF%BC%89%5E1999%2B%EF%BC%88-2%EF%BC%89%5E2000%E7%AD%89%E4%BA%8E%EF%BC%88+%EF%BC%89%EF%BC%882%EF%BC%89%EF%BC%885%2F8%EF%BC%89%5E2004%2A%EF%BC%88-1.6%EF%BC%89%5E2005%2F%EF%BC%88-1%EF%BC%89%5E2003%3D%EF%BC%88+%EF%BC%89%EF%BC%883%EF%BC%89%E5%B7%B2%E7%9F%A5a1%2Ba2%3D1%2Ca2%2Ba3%3D2%2Ca3%2Ba4%3D3%2C%E2%80%A6%2Ca99%2Ba100%3D99%2Ca100%2Ba1%3D100%2C%E9%82%A3%E4%B9%88a1%2Ba2%2Ba3%2B%E2%80%A6%2Ba100%3D%28+%29%284%29%E8%8B%A5x%5E2%2B3x-1%3D0%2C%E5%88%99x%5E3%2B5x%5E2%2B5x%2B18%3D%EF%BC%88+%EF%BC%89)
(1)计算(-2)^1999+(-2)^2000等于( )(2)(5/8)^2004*(-1.6)^2005/(-1)^2003=( )(3)已知a1+a2=1,a2+a3=2,a3+a4=3,…,a99+a100=99,a100+a1=100,那么a1+a2+a3+…+a100=( )(4)若x^2+3x-1=0,则x^3+5x^2+5x+18=( )
(1)计算(-2)^1999+(-2)^2000等于( )
(2)(5/8)^2004*(-1.6)^2005/(-1)^2003=( )
(3)已知a1+a2=1,a2+a3=2,a3+a4=3,…,a99+a100=99,a100+a1=100,那么a1+a2+a3+…+a100=( )
(4)若x^2+3x-1=0,则x^3+5x^2+5x+18=( )
(1)计算(-2)^1999+(-2)^2000等于( )(2)(5/8)^2004*(-1.6)^2005/(-1)^2003=( )(3)已知a1+a2=1,a2+a3=2,a3+a4=3,…,a99+a100=99,a100+a1=100,那么a1+a2+a3+…+a100=( )(4)若x^2+3x-1=0,则x^3+5x^2+5x+18=( )
(1)(-2)^1999[1+(-2)]=2^1999
(2)[(5/8)*(-8/5)]^2004*(-1.6)*(-1)=1.6
(3)a1+a2+a2+a3+……+a99+a100+a100+a1=1+2+3+……+100
即:2(a1+a2+a3+……+a100)=(1+100)*100/2
所以(a1+a2+a3+……+a100)=2525
(4)因为x^2+3x=1
原式=x^3+3x^2+2x^2+5x+18
=x(x^2+3x)+2x^2+5x+18
=x+2x^2+5x+18
=2(x^2+3x)+18
=2+18
=20
(1)(-2)^1999=-2^1999;(-2)^2000=2^2000;原式=2^2000-2^1999=2^1999x(2-1)=2^1999
(2)原式=(5/8)^2004*(-8/5)^2005/(-1)=(5^2004/8^2004)(8^2005/5^2005)=8/5
(3)所有的式子左右两边分别相加有:2(a1+a2+a3+...+a100)=1+2+3+......
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(1)(-2)^1999=-2^1999;(-2)^2000=2^2000;原式=2^2000-2^1999=2^1999x(2-1)=2^1999
(2)原式=(5/8)^2004*(-8/5)^2005/(-1)=(5^2004/8^2004)(8^2005/5^2005)=8/5
(3)所有的式子左右两边分别相加有:2(a1+a2+a3+...+a100)=1+2+3+...+100=(1+100)100/2 =5050 求得(a1+a2+a3+...+a100)=2525.
(4)x^3+5x^2+5x+18=(x+2)(x^2+3x-1)+20=20.
收起
(1)2∧1999
(2)1.6
(3)2525
(4)20