已知f(x)=2sin(2x+派/6)+a+1(a为常数) 1.若x属于[0,派/2]时,f(x)的最大值为4,求a的值已知f(x)=2sin(2x+派/6)+a+1(a为常数)1.若x属于[0,派/2]时,f(x)的最大值为4,求a的值 2.求出使f(x)取最大值时x的集合
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![已知f(x)=2sin(2x+派/6)+a+1(a为常数) 1.若x属于[0,派/2]时,f(x)的最大值为4,求a的值已知f(x)=2sin(2x+派/6)+a+1(a为常数)1.若x属于[0,派/2]时,f(x)的最大值为4,求a的值 2.求出使f(x)取最大值时x的集合](/uploads/image/z/7304597-53-7.jpg?t=%E5%B7%B2%E7%9F%A5f%28x%29%3D2sin%282x%2B%E6%B4%BE%2F6%29%2Ba%2B1%EF%BC%88a%E4%B8%BA%E5%B8%B8%E6%95%B0%EF%BC%89+1.%E8%8B%A5x%E5%B1%9E%E4%BA%8E%5B0%2C%E6%B4%BE%2F2%5D%E6%97%B6%2Cf%28x%29%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC%E4%B8%BA4%2C%E6%B1%82a%E7%9A%84%E5%80%BC%E5%B7%B2%E7%9F%A5f%28x%29%3D2sin%282x%2B%E6%B4%BE%2F6%29%2Ba%2B1%EF%BC%88a%E4%B8%BA%E5%B8%B8%E6%95%B0%EF%BC%891.%E8%8B%A5x%E5%B1%9E%E4%BA%8E%5B0%2C%E6%B4%BE%2F2%5D%E6%97%B6%2Cf%28x%29%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC%E4%B8%BA4%2C%E6%B1%82a%E7%9A%84%E5%80%BC+2.%E6%B1%82%E5%87%BA%E4%BD%BFf%EF%BC%88x%EF%BC%89%E5%8F%96%E6%9C%80%E5%A4%A7%E5%80%BC%E6%97%B6x%E7%9A%84%E9%9B%86%E5%90%88)
已知f(x)=2sin(2x+派/6)+a+1(a为常数) 1.若x属于[0,派/2]时,f(x)的最大值为4,求a的值已知f(x)=2sin(2x+派/6)+a+1(a为常数)1.若x属于[0,派/2]时,f(x)的最大值为4,求a的值 2.求出使f(x)取最大值时x的集合
已知f(x)=2sin(2x+派/6)+a+1(a为常数) 1.若x属于[0,派/2]时,f(x)的最大值为4,求a的值
已知f(x)=2sin(2x+派/6)+a+1(a为常数)
1.若x属于[0,派/2]时,f(x)的最大值为4,求a的值
2.求出使f(x)取最大值时x的集合
已知f(x)=2sin(2x+派/6)+a+1(a为常数) 1.若x属于[0,派/2]时,f(x)的最大值为4,求a的值已知f(x)=2sin(2x+派/6)+a+1(a为常数)1.若x属于[0,派/2]时,f(x)的最大值为4,求a的值 2.求出使f(x)取最大值时x的集合
1,0
1.因为x属于[0,派/2],所以(2x+派/6)属于[派/6,7派/6],所以sin(2x+派/6)最大值是1,那么就有f(x)的最大值=2+a+1=4,故a=1.
2.f(x)=2sin(2x+派/6)+2,当2x+π/6=2kπ+π/2是f(x)有最大值,k为整数,所以
x=kπ+π/6,k为整数时,f(x)有最大值。