(a+b+c)²*(1/a+1/b+1/c)=0,是怎么得到[1+2(ab+ac+bc)]*(ab+ac+bc)/abc=0的?详解...
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![(a+b+c)²*(1/a+1/b+1/c)=0,是怎么得到[1+2(ab+ac+bc)]*(ab+ac+bc)/abc=0的?详解...](/uploads/image/z/7176113-17-3.jpg?t=%28a%2Bb%2Bc%29%26%23178%3B%2A%281%2Fa%2B1%2Fb%2B1%2Fc%29%3D0%2C%E6%98%AF%E6%80%8E%E4%B9%88%E5%BE%97%E5%88%B0%5B1%2B2%28ab%2Bac%2Bbc%EF%BC%89%5D%2A%28ab%2Bac%2Bbc%29%2Fabc%3D0%E7%9A%84%3F%E8%AF%A6%E8%A7%A3...)
(a+b+c)²*(1/a+1/b+1/c)=0,是怎么得到[1+2(ab+ac+bc)]*(ab+ac+bc)/abc=0的?详解...
(a+b+c)²*(1/a+1/b+1/c)=0,是怎么得到[1+2(ab+ac+bc)]*(ab+ac+bc)/abc=0的?详解...
(a+b+c)²*(1/a+1/b+1/c)=0,是怎么得到[1+2(ab+ac+bc)]*(ab+ac+bc)/abc=0的?详解...
(a+b+c)²=[(a+b)+c]²=a²+b²+c²+2(ab+ac+bc)
1/a+1/b+1/c=ab/abc+ac/abc+bc/abc=(ab+ac+bc)/abc
另外题目中肯定有a²+b²+c²=1