计算∫dx/[1+(1-x^2)^1/2]?∫dx/[1+(1-x^2)^1/2] (解题时设x=sint)求结果的时候(t=arcsinx)有一项是tan(t/2)需要把t带进去求最后的值!但是tan(t/2)我算的结果是(1+(1-x^2)^0.5)/x 和 (1-(1-x^2)^0.5)/x,而
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![计算∫dx/[1+(1-x^2)^1/2]?∫dx/[1+(1-x^2)^1/2] (解题时设x=sint)求结果的时候(t=arcsinx)有一项是tan(t/2)需要把t带进去求最后的值!但是tan(t/2)我算的结果是(1+(1-x^2)^0.5)/x 和 (1-(1-x^2)^0.5)/x,而](/uploads/image/z/7143293-29-3.jpg?t=%E8%AE%A1%E7%AE%97%E2%88%ABdx%2F%5B1%2B%281-x%5E2%29%5E1%2F2%5D%3F%E2%88%ABdx%2F%5B1%2B%281-x%5E2%29%5E1%2F2%5D+%EF%BC%88%E8%A7%A3%E9%A2%98%E6%97%B6%E8%AE%BEx%3Dsint%EF%BC%89%E6%B1%82%E7%BB%93%E6%9E%9C%E7%9A%84%E6%97%B6%E5%80%99%EF%BC%88t%3Darcsinx%EF%BC%89%E6%9C%89%E4%B8%80%E9%A1%B9%E6%98%AFtan%EF%BC%88t%2F2%EF%BC%89%E9%9C%80%E8%A6%81%E6%8A%8At%E5%B8%A6%E8%BF%9B%E5%8E%BB%E6%B1%82%E6%9C%80%E5%90%8E%E7%9A%84%E5%80%BC%21%E4%BD%86%E6%98%AFtan%EF%BC%88t%2F2%EF%BC%89%E6%88%91%E7%AE%97%E7%9A%84%E7%BB%93%E6%9E%9C%E6%98%AF%281%2B%EF%BC%881-x%5E2%29%5E0.5%29%2Fx+%E5%92%8C+%281-%EF%BC%881-x%5E2%29%5E0.5%29%2Fx%2C%E8%80%8C)
计算∫dx/[1+(1-x^2)^1/2]?∫dx/[1+(1-x^2)^1/2] (解题时设x=sint)求结果的时候(t=arcsinx)有一项是tan(t/2)需要把t带进去求最后的值!但是tan(t/2)我算的结果是(1+(1-x^2)^0.5)/x 和 (1-(1-x^2)^0.5)/x,而
计算∫dx/[1+(1-x^2)^1/2]?
∫dx/[1+(1-x^2)^1/2] (解题时设x=sint)
求结果的时候(t=arcsinx)有一项是tan(t/2)需要把t带进去求最后的值!但是tan(t/2)我算的结果是(1+(1-x^2)^0.5)/x 和
(1-(1-x^2)^0.5)/x,而答案只取了后者,为什么?是我算错了?
计算∫dx/[1+(1-x^2)^1/2]?∫dx/[1+(1-x^2)^1/2] (解题时设x=sint)求结果的时候(t=arcsinx)有一项是tan(t/2)需要把t带进去求最后的值!但是tan(t/2)我算的结果是(1+(1-x^2)^0.5)/x 和 (1-(1-x^2)^0.5)/x,而
设 x = sint,-PI/2
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