从(1)(2)(3)中你能得出什么猜想?你能证明你的猜想吗?(1)方程x^2+2x+1=0的根为X1= X2= X1+X2= X1X2=(2)方程x^2-3x-1=0的根为X1= X2= X1+X2= X1X2= (3)方程3x^2+4x-7=0的根为X1= X2= X1+X2= X1X2= 由上述
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/04 01:52:36
![从(1)(2)(3)中你能得出什么猜想?你能证明你的猜想吗?(1)方程x^2+2x+1=0的根为X1= X2= X1+X2= X1X2=(2)方程x^2-3x-1=0的根为X1= X2= X1+X2= X1X2= (3)方程3x^2+4x-7=0的根为X1= X2= X1+X2= X1X2= 由上述](/uploads/image/z/7135453-37-3.jpg?t=%E4%BB%8E%EF%BC%881%EF%BC%89%EF%BC%882%EF%BC%89%EF%BC%883%EF%BC%89%E4%B8%AD%E4%BD%A0%E8%83%BD%E5%BE%97%E5%87%BA%E4%BB%80%E4%B9%88%E7%8C%9C%E6%83%B3%3F%E4%BD%A0%E8%83%BD%E8%AF%81%E6%98%8E%E4%BD%A0%E7%9A%84%E7%8C%9C%E6%83%B3%E5%90%97%3F%EF%BC%881%EF%BC%89%E6%96%B9%E7%A8%8Bx%5E2%2B2x%2B1%3D0%E7%9A%84%E6%A0%B9%E4%B8%BAX1%3D+X2%3D+X1%2BX2%3D+X1X2%3D%EF%BC%882%EF%BC%89%E6%96%B9%E7%A8%8Bx%5E2-3x-1%3D0%E7%9A%84%E6%A0%B9%E4%B8%BAX1%3D+X2%3D+X1%2BX2%3D+X1X2%3D+%EF%BC%883%EF%BC%89%E6%96%B9%E7%A8%8B3x%5E2%2B4x-7%3D0%E7%9A%84%E6%A0%B9%E4%B8%BAX1%3D+X2%3D+X1%2BX2%3D+X1X2%3D+%E7%94%B1%E4%B8%8A%E8%BF%B0)
从(1)(2)(3)中你能得出什么猜想?你能证明你的猜想吗?(1)方程x^2+2x+1=0的根为X1= X2= X1+X2= X1X2=(2)方程x^2-3x-1=0的根为X1= X2= X1+X2= X1X2= (3)方程3x^2+4x-7=0的根为X1= X2= X1+X2= X1X2= 由上述
从(1)(2)(3)中你能得出什么猜想?你能证明你的猜想吗?
(1)方程x^2+2x+1=0的根为X1= X2= X1+X2= X1X2=
(2)方程x^2-3x-1=0的根为X1= X2= X1+X2= X1X2=
(3)方程3x^2+4x-7=0的根为X1= X2= X1+X2= X1X2=
由上述的你能得出什么猜想 你能证明你的猜想吗?【主要是猜想,嗯嗯嗯嗯嗯嗯~
从(1)(2)(3)中你能得出什么猜想?你能证明你的猜想吗?(1)方程x^2+2x+1=0的根为X1= X2= X1+X2= X1X2=(2)方程x^2-3x-1=0的根为X1= X2= X1+X2= X1X2= (3)方程3x^2+4x-7=0的根为X1= X2= X1+X2= X1X2= 由上述
猜出韦达定理
x1+x2=-b/a x1x2=c/a