1.若a+b+c,b+c-a,c+a-b,a+b-c成等比,且公比为q,则q^3+q^2+q=?2.求数列1/2,11/4,39/8,127/16……的前n项和
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![1.若a+b+c,b+c-a,c+a-b,a+b-c成等比,且公比为q,则q^3+q^2+q=?2.求数列1/2,11/4,39/8,127/16……的前n项和](/uploads/image/z/7125940-28-0.jpg?t=1.%E8%8B%A5a%2Bb%2Bc%2Cb%2Bc-a%2Cc%2Ba-b%2Ca%2Bb-c%E6%88%90%E7%AD%89%E6%AF%94%2C%E4%B8%94%E5%85%AC%E6%AF%94%E4%B8%BAq%2C%E5%88%99q%5E3%2Bq%5E2%2Bq%3D%3F2.%E6%B1%82%E6%95%B0%E5%88%971%2F2%2C11%2F4%2C39%2F8%2C127%2F16%E2%80%A6%E2%80%A6%E7%9A%84%E5%89%8Dn%E9%A1%B9%E5%92%8C)
1.若a+b+c,b+c-a,c+a-b,a+b-c成等比,且公比为q,则q^3+q^2+q=?2.求数列1/2,11/4,39/8,127/16……的前n项和
1.若a+b+c,b+c-a,c+a-b,a+b-c成等比,且公比为q,则q^3+q^2+q=?
2.求数列1/2,11/4,39/8,127/16……的前n项和
1.若a+b+c,b+c-a,c+a-b,a+b-c成等比,且公比为q,则q^3+q^2+q=?2.求数列1/2,11/4,39/8,127/16……的前n项和
1.根据等比条件:设为a1,a2,a3,a4
a2=a1*q.a4=a1*q^3
q^3+q^2+q=(a4+a3+a2)/a1
=(a+b+c)/(a+b+c)=1
|c-b|+|a-c|-|b+c|,(c
|a+b|-|c| |a-c|-|b-a|+|a+c|c
若a>b,c
若a>b,c
若a>b,c
若a>b,c
若a>b,c
若a>b,c
a,b,c(a
[b/(a-b+c)]+[(2a+c)/(b-a-c)]-[(b-c)/(b-a-c)]
计算:a/[(a-b)(b-c)]+b/[(b-c)(b-a)]+c/[(c-a)(c-d)]
b/a-b+c+2a+c/b-a-c-b-c/b-c-a
(a-b-c)(b+c-a)(c-a+b)=
请化简|a-b-c|+|b-c-a|+|c-a-b|.
计算(c-a)/(a-b)(b-c)+(a-b)/(b-c)(c-a)+(b-c)/(c-a)(a-b)
化简:a+b/(a-c)(b-c)-b+c/(a-b)(c-a)+c+a/(c-b)(a-b)
a+b/(b-c)(c-a);b+c/(b-a)(a-c);a+c/(a-b)(b-c) 求 通分
证明;(a+b)/(a-b)+(b+c)/(b-c)+(c+a)/(c-a)+[(a+b)(b+c)(c+b)/(a-b)(b-c)(c-a)]=0