解方程:x²+3x+根号下(x²+3x)=6还有x²-(2+√3)x+2√3=0
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![解方程:x²+3x+根号下(x²+3x)=6还有x²-(2+√3)x+2√3=0](/uploads/image/z/699868-28-8.jpg?t=%E8%A7%A3%E6%96%B9%E7%A8%8B%EF%BC%9Ax%26%23178%3B%2B3x%2B%E6%A0%B9%E5%8F%B7%E4%B8%8B%EF%BC%88x%26%23178%3B%2B3x%EF%BC%89%3D6%E8%BF%98%E6%9C%89x%26%23178%3B-%282%2B%E2%88%9A3%29x%2B2%E2%88%9A3%3D0)
解方程:x²+3x+根号下(x²+3x)=6还有x²-(2+√3)x+2√3=0
解方程:x²+3x+根号下(x²+3x)=6
还有x²-(2+√3)x+2√3=0
解方程:x²+3x+根号下(x²+3x)=6还有x²-(2+√3)x+2√3=0
x²+3x+(x²+3x)^(1/2)=6
设t=(x²+3x)^(1/2) 则 t>=0
t^2+t=6
(t-2)(t+3)=0
t=2; t=-3(舍弃)
x^2+3x=2^2
x^2+3x-4=0
(x-1)(x+4)=0
x=1,x=-4