化简:第一题:a²/a²+2a乘(a²/a-2)-4/a-2)第二题:1/x-3减去6/x²-9减去x+1/6+2x
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![化简:第一题:a²/a²+2a乘(a²/a-2)-4/a-2)第二题:1/x-3减去6/x²-9减去x+1/6+2x](/uploads/image/z/6910643-11-3.jpg?t=%E5%8C%96%E7%AE%80%EF%BC%9A%E7%AC%AC%E4%B8%80%E9%A2%98%EF%BC%9Aa%26%23178%3B%2Fa%26%23178%3B%2B2a%E4%B9%98%EF%BC%88a%26%23178%3B%2Fa-2%EF%BC%89-4%2Fa-2%EF%BC%89%E7%AC%AC%E4%BA%8C%E9%A2%98%EF%BC%9A1%2Fx-3%E5%87%8F%E5%8E%BB6%2Fx%26%23178%3B-9%E5%87%8F%E5%8E%BBx%2B1%2F6%2B2x)
化简:第一题:a²/a²+2a乘(a²/a-2)-4/a-2)第二题:1/x-3减去6/x²-9减去x+1/6+2x
化简:第一题:a²/a²+2a乘(a²/a-2)-4/a-2)第二题:1/x-3减去6/x²-9减去x+1/6+2x
化简:第一题:a²/a²+2a乘(a²/a-2)-4/a-2)第二题:1/x-3减去6/x²-9减去x+1/6+2x
1、原式=a/(a+2)*[a²/(a-2)-4/(a-2)]
=a/(a+2)*[(a²-4)/(a-2)]
=a/(a+2)*[(a+2)(a-2)/(a-2)]
=a
2、原式=1/(x-3)-6/(x+3)(x-3)-(x+1)/2(x+3)
=[2(x+3)-12-(x+1)(x-3)]/(x²-9)
=(2x+6-12-x²+2x+3)/(x²-9)
=-(x²-4x-9)/(x²-9)
=4x/(x²-9)-1
问题严谨点,没看懂什么意思。括号写规范点!不要用汉字表示,请用数字符号及括号!