1、当-2<X<5时,化简|x-5|-|x+2|.2、若|a-1|+(ab-2)²=0,计算如下代数式.1/ab+1/(a+1)(b+1)+1/(a+2)+(b+2)+……+1\(a+2001)(b+2001)3、若(x-2)(x+3)=0,则x的值为多少?4、四个互不相等的整数a、b、c、d的积
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![1、当-2<X<5时,化简|x-5|-|x+2|.2、若|a-1|+(ab-2)²=0,计算如下代数式.1/ab+1/(a+1)(b+1)+1/(a+2)+(b+2)+……+1\(a+2001)(b+2001)3、若(x-2)(x+3)=0,则x的值为多少?4、四个互不相等的整数a、b、c、d的积](/uploads/image/z/625344-24-4.jpg?t=1%E3%80%81%E5%BD%93%EF%BC%8D2%EF%BC%9CX%EF%BC%9C5%E6%97%B6%2C%E5%8C%96%E7%AE%80%EF%BD%9Cx-5%EF%BD%9C-%EF%BD%9Cx%2B2%EF%BD%9C.2%E3%80%81%E8%8B%A5%EF%BD%9Ca-1%EF%BD%9C%2B%28ab-2%29%26sup2%3B%3D0%2C%E8%AE%A1%E7%AE%97%E5%A6%82%E4%B8%8B%E4%BB%A3%E6%95%B0%E5%BC%8F.1%2Fab%2B1%2F%28a%2B1%29%28b%2B1%29%2B1%2F%28a%2B2%29%2B%28b%2B2%29%2B%E2%80%A6%E2%80%A6%2B1%5C%28a%2B2001%29%28b%2B2001%293%E3%80%81%E8%8B%A5%28x-2%29%28x%2B3%29%3D0%2C%E5%88%99x%E7%9A%84%E5%80%BC%E4%B8%BA%E5%A4%9A%E5%B0%91%3F4%E3%80%81%E5%9B%9B%E4%B8%AA%E4%BA%92%E4%B8%8D%E7%9B%B8%E7%AD%89%E7%9A%84%E6%95%B4%E6%95%B0a%E3%80%81b%E3%80%81c%E3%80%81d%E7%9A%84%E7%A7%AF)
1、当-2<X<5时,化简|x-5|-|x+2|.2、若|a-1|+(ab-2)²=0,计算如下代数式.1/ab+1/(a+1)(b+1)+1/(a+2)+(b+2)+……+1\(a+2001)(b+2001)3、若(x-2)(x+3)=0,则x的值为多少?4、四个互不相等的整数a、b、c、d的积
1、当-2<X<5时,化简|x-5|-|x+2|.
2、若|a-1|+(ab-2)²=0,计算如下代数式.
1/ab+1/(a+1)(b+1)+1/(a+2)+(b+2)+……+1\(a+2001)(b+2001)
3、若(x-2)(x+3)=0,则x的值为多少?
4、四个互不相等的整数a、b、c、d的积是9,则a+b+c+d的值是多少?
1、当-2<X<5时,化简|x-5|-|x+2|.2、若|a-1|+(ab-2)²=0,计算如下代数式.1/ab+1/(a+1)(b+1)+1/(a+2)+(b+2)+……+1\(a+2001)(b+2001)3、若(x-2)(x+3)=0,则x的值为多少?4、四个互不相等的整数a、b、c、d的积
1.-2x+3
2.2002/2003
3.2,-3
4.0
1.因为-2
0
|x-5|-|x+2|=5-x-x-2=3-2x
2.
1 5-x-x-2=3-2x
2 两个非负相加的和为0,则分别为0。所以a=1,b=2.,原式1/2+1/2*3+1/3*4。。。。列项相消,答案为2002/2003
3 x=2,x=-3
4 只能是1 -1 3 -3 答案为0
1、
因为-2<X<5
|x-5|-|x+2|
=-(x-5)-(x+2)
=-x+5-x-2
=-2x+3
2、|a-1|+(ab-2)²=0
a-1=0 ab-2=0
a=1,b=2
把a=1,b=2代入式子
1/ab+1/(a+1)(b+1)+1/(a+2)+(b+2)+……+1\(a+2001)(...
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1、
因为-2<X<5
|x-5|-|x+2|
=-(x-5)-(x+2)
=-x+5-x-2
=-2x+3
2、|a-1|+(ab-2)²=0
a-1=0 ab-2=0
a=1,b=2
把a=1,b=2代入式子
1/ab+1/(a+1)(b+1)+1/(a+2)+(b+2)+……+1\(a+2001)(b+2001)
=1/2+1/(2×3)+1/(3×4)+.......+1/(2002×2003)
=1/2+1/2-1/3+1/3-1/4+......+1/2002-1/2003
=1/2+1/2-1/2003
=2002/2003
3、(x-2)(x+3)=0
x-2=0或者x+3=0
x=2或者x=-3
4、因为a,b,c,d为四个互不相等的整数
所以根据9=1×9=1×3×3
1=1×1或1=-1×(-1)
3=1×3或3=-1×(-3)
所以9=-1×(-3)×1×3
那么a+b+c+d=-1+1-3+3=0
收起
1. 1
2. 0
3. 2/-3
4. 0