设P:实数x满足x^2-4ax+3a^20,命题q:实数x满足x^2-x-60,(1)若a=5/2,且p并q为假,p或q为真,求实数x的取值范围(2)非p是非q的充分不必要条件,a的范围
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![设P:实数x满足x^2-4ax+3a^20,命题q:实数x满足x^2-x-60,(1)若a=5/2,且p并q为假,p或q为真,求实数x的取值范围(2)非p是非q的充分不必要条件,a的范围](/uploads/image/z/6076232-8-2.jpg?t=%E8%AE%BEP%EF%BC%9A%E5%AE%9E%E6%95%B0x%E6%BB%A1%E8%B6%B3x%5E2-4ax%2B3a%5E20%2C%E5%91%BD%E9%A2%98q%3A%E5%AE%9E%E6%95%B0x%E6%BB%A1%E8%B6%B3x%5E2-x-60%2C%281%29%E8%8B%A5a%3D5%2F2%2C%E4%B8%94p%E5%B9%B6q%E4%B8%BA%E5%81%87%2Cp%E6%88%96q%E4%B8%BA%E7%9C%9F%2C%E6%B1%82%E5%AE%9E%E6%95%B0x%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%282%29%E9%9D%9Ep%E6%98%AF%E9%9D%9Eq%E7%9A%84%E5%85%85%E5%88%86%E4%B8%8D%E5%BF%85%E8%A6%81%E6%9D%A1%E4%BB%B6%2Ca%E7%9A%84%E8%8C%83%E5%9B%B4)
设P:实数x满足x^2-4ax+3a^20,命题q:实数x满足x^2-x-60,(1)若a=5/2,且p并q为假,p或q为真,求实数x的取值范围(2)非p是非q的充分不必要条件,a的范围
设P:实数x满足x^2-4ax+3a^2<0,其中a>0,命题q:实数x满足x^2-x-6<=0,x^2+2x-8>0,(1)若a=5/2,且p并q为假,p或q为真,求实数x的取值范围(2)非p是非q的充分不必要条件,a的范围
设P:实数x满足x^2-4ax+3a^20,命题q:实数x满足x^2-x-60,(1)若a=5/2,且p并q为假,p或q为真,求实数x的取值范围(2)非p是非q的充分不必要条件,a的范围
(1)a=1时,命题p:x2-4x+3<01<x<3命题q:{x2-x-6≤0x2+2x-8>0{-2≤x≤3x<-4或x>22<x≤3,p∧q为真,即p和q均为真,故实数x的取值范围是2<x<3(2)﹁p是﹁q的充分不必要条件q是p的充分不必要条件,即qp,反之不成立.即q中的不等式的解集是p中的不等式解集的子集.由(1)知命题q:2<x≤3,命题p:实数x满足x2-4ax+3a2<0(x-a)(x-3a)<0由题意a>0,所以命题p:a<x<3a,所以{a≤23a>3,所以1<a≤2
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设命题p:实数x满足x^2-4ax+3a^2
设p:实数x满足x^2-4ax+3a^2
设p:实数x满足x^2-4ax+3a^2
设P:实数x满足x^2-4ax+3a^20,命题q:实数x满足x^2-x-60,若a设P:实数x满足x^2-4ax+3a^20,命题q:实数x满足x^2-x-60,(1)若a=2.5,且p^q为假 pvq真,求实数x的取值范围
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设P:实数x满足x^2-4ax+3a^20,命题q:实数x满足x^2-x-60,若a设P:实数x满足x^2-4ax+3a^20,命题q:实数x满足x^2-x-60,(1)若a=1,且p^q为真,求实数x的取值范围(2)非p是非q的充分不必要条件,a的范围
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设P:实数x满足x^2-4ax+3a^20,若非p是非q的必要不充分条件,求a范围
:已知命题p:实数x满足x^2-4ax+3a^2
已知命题p:实数x满足x^2-4ax+3a^2
命题p:实数x满足x^2-4ax+3a^2
已知命题p:实数x满足x^2-4ax+3a^2
命题p:实数x满足x^2-4ax+3a^2
命题p:实数x满足x^2-4ax+3a^2
设命题p:实数x满足x^2-4ax+3a^20……详细如下设命题p:实数x满足x^2-4ax+3a^2<0,命题q:实数x满足方程x^2-x-6≤0和方程x^2+2x-8>0,(①)若a=1,p且q为真,求实数x的取值范围;(②)若非p是非q的充分
已知p:实数x满足x^2-4ax+3a^20);q:实数x满足x^2-5x+6