已知a>0,a不等于1,f(x)满足f(log aX)=[a(x2-1)]/[x(a2-1)],求解y=f(x)的解析式和奇偶性
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![已知a>0,a不等于1,f(x)满足f(log aX)=[a(x2-1)]/[x(a2-1)],求解y=f(x)的解析式和奇偶性](/uploads/image/z/5928897-57-7.jpg?t=%E5%B7%B2%E7%9F%A5a%3E0%2Ca%E4%B8%8D%E7%AD%89%E4%BA%8E1%2Cf%28x%29%E6%BB%A1%E8%B6%B3f%28log+aX%29%3D%5Ba%28x2-1%29%5D%2F%5Bx%28a2-1%29%5D%2C%E6%B1%82%E8%A7%A3y%3Df%28x%EF%BC%89%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F%E5%92%8C%E5%A5%87%E5%81%B6%E6%80%A7)
已知a>0,a不等于1,f(x)满足f(log aX)=[a(x2-1)]/[x(a2-1)],求解y=f(x)的解析式和奇偶性
已知a>0,a不等于1,f(x)满足f(log aX)=[a(x2-1)]/[x(a2-1)],求解y=f(x)的解析式和奇偶性
已知a>0,a不等于1,f(x)满足f(log aX)=[a(x2-1)]/[x(a2-1)],求解y=f(x)的解析式和奇偶性
像这样的题你只要令t=log aX,然后用t表示x ,再代回原来的表达式,再把t写成x就可以了.
其实我很想帮你做的,不过你的表达式我有点不太清楚.不好意思了~~