设a,b,c>0,且3^a=4^b=5^c,则以下四个式子中恒成立的是A1/c=1/a+1/b B2/c=2/a+1/b C1/c=2/a+2/b D2/c=1/a+2/b我觉得这几个式子都错啊,
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![设a,b,c>0,且3^a=4^b=5^c,则以下四个式子中恒成立的是A1/c=1/a+1/b B2/c=2/a+1/b C1/c=2/a+2/b D2/c=1/a+2/b我觉得这几个式子都错啊,](/uploads/image/z/5609203-43-3.jpg?t=%E8%AE%BEa%2Cb%2Cc%3E0%2C%E4%B8%943%5Ea%3D4%5Eb%3D5%5Ec%2C%E5%88%99%E4%BB%A5%E4%B8%8B%E5%9B%9B%E4%B8%AA%E5%BC%8F%E5%AD%90%E4%B8%AD%E6%81%92%E6%88%90%E7%AB%8B%E7%9A%84%E6%98%AFA1%2Fc%3D1%2Fa%2B1%2Fb+B2%2Fc%3D2%2Fa%2B1%2Fb+C1%2Fc%3D2%2Fa%2B2%2Fb+D2%2Fc%3D1%2Fa%2B2%2Fb%E6%88%91%E8%A7%89%E5%BE%97%E8%BF%99%E5%87%A0%E4%B8%AA%E5%BC%8F%E5%AD%90%E9%83%BD%E9%94%99%E5%95%8A%2C)
设a,b,c>0,且3^a=4^b=5^c,则以下四个式子中恒成立的是A1/c=1/a+1/b B2/c=2/a+1/b C1/c=2/a+2/b D2/c=1/a+2/b我觉得这几个式子都错啊,
设a,b,c>0,且3^a=4^b=5^c,则以下四个式子中恒成立的是
A1/c=1/a+1/b B2/c=2/a+1/b C1/c=2/a+2/b D2/c=1/a+2/b
我觉得这几个式子都错啊,
设a,b,c>0,且3^a=4^b=5^c,则以下四个式子中恒成立的是A1/c=1/a+1/b B2/c=2/a+1/b C1/c=2/a+2/b D2/c=1/a+2/b我觉得这几个式子都错啊,
3^a=4^b=5^c=k
则a=logk3 b=logk4 c=logk5
代入是都不对