解下列方程:(1)x²-15x=100 (2)(2x²-1)²-1=0 (3)(x-1)²-18=0(4)3(x-5)²=2(5-x)用因式分解法解下列一元二次方程(1)9t²-(t-1)²=0
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![解下列方程:(1)x²-15x=100 (2)(2x²-1)²-1=0 (3)(x-1)²-18=0(4)3(x-5)²=2(5-x)用因式分解法解下列一元二次方程(1)9t²-(t-1)²=0](/uploads/image/z/558763-43-3.jpg?t=%E8%A7%A3%E4%B8%8B%E5%88%97%E6%96%B9%E7%A8%8B%EF%BC%9A%EF%BC%881%EF%BC%89x%26%23178%3B-15x%3D100+%EF%BC%882%EF%BC%89%EF%BC%882x%26%23178%3B-1%EF%BC%89%26%23178%3B-1%3D0+%EF%BC%883%EF%BC%89%EF%BC%88x-1%29%26%23178%3B-18%3D0%EF%BC%884%EF%BC%893%EF%BC%88x-5%EF%BC%89%26%23178%3B%3D2%EF%BC%885-x%EF%BC%89%E7%94%A8%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3%E6%B3%95%E8%A7%A3%E4%B8%8B%E5%88%97%E4%B8%80%E5%85%83%E4%BA%8C%E6%AC%A1%E6%96%B9%E7%A8%8B%EF%BC%881%EF%BC%899t%26%23178%3B-%EF%BC%88t-1%29%26%23178%3B%3D0)
解下列方程:(1)x²-15x=100 (2)(2x²-1)²-1=0 (3)(x-1)²-18=0(4)3(x-5)²=2(5-x)用因式分解法解下列一元二次方程(1)9t²-(t-1)²=0
解下列方程:(1)x²-15x=100 (2)(2x²-1)²-1=0 (3)(x-1)²-18=0
(4)3(x-5)²=2(5-x)
用因式分解法解下列一元二次方程
(1)9t²-(t-1)²=0
解下列方程:(1)x²-15x=100 (2)(2x²-1)²-1=0 (3)(x-1)²-18=0(4)3(x-5)²=2(5-x)用因式分解法解下列一元二次方程(1)9t²-(t-1)²=0
(1)x²-15x=100
x²-15x-100 =0
(x-20)(x+5)=0
x1=20 x2=-5
(2)(2x²-1)²-1=0
(2x²-1)²=1
2x²-1=±1
2x²=0或2x²=2
x²=0或x²=1
x1=0 x2=1 x3=-1
(3)(x-1)²-18=0
(x-1)²=18
x-1=±3√2
x1=1+3√2 x2=1-3√2
(4)3(x-5)²=2(5-x)
3(x-5)²+2(x-5)=0
(x-5)(3x-15+2)=0
(x-5)(3x-13)=0
x1=5 x2=13/3
用因式分解法解下列一元二次方程
(1)9t²-(t-1)²=0
(3t)²-(t-1)²=0
(3t+t-1)(3t-t+1)=0
(4t-1)(2t+1)=0
t1=1/4 t2=-1/2