已知sinx=1/2+cosx,则cos2x/√2sin(x+π/4)的值为
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![已知sinx=1/2+cosx,则cos2x/√2sin(x+π/4)的值为](/uploads/image/z/5528832-24-2.jpg?t=%E5%B7%B2%E7%9F%A5sinx%3D1%2F2%2Bcosx%2C%E5%88%99cos2x%2F%E2%88%9A2sin%28x%2B%CF%80%2F4%29%E7%9A%84%E5%80%BC%E4%B8%BA)
已知sinx=1/2+cosx,则cos2x/√2sin(x+π/4)的值为
已知sinx=1/2+cosx,则cos2x/√2sin(x+π/4)的值为
已知sinx=1/2+cosx,则cos2x/√2sin(x+π/4)的值为
cos2x/√2sin(x+π/4)
=[(cosx)^2-(sinx)^2]/√2[√2/2sinx+√2/2cosx]
=[(cosx)^2-(sinx)^2]/[sinx+cosx]
=cosx-sinx=-1/2