-1/2a=b与(-2-b)²+(3-b)²=(a+b+3)/2 +2联立,
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/30 11:54:58
![-1/2a=b与(-2-b)²+(3-b)²=(a+b+3)/2 +2联立,](/uploads/image/z/5301790-70-0.jpg?t=-1%2F2a%3Db%E4%B8%8E%EF%BC%88-2-b%EF%BC%89%26%23178%3B%2B%EF%BC%883-b%EF%BC%89%26%23178%3B%3D%EF%BC%88a%2Bb%2B3%EF%BC%89%2F2+%2B2%E8%81%94%E7%AB%8B%2C)
-1/2a=b与(-2-b)²+(3-b)²=(a+b+3)/2 +2联立,
-1/2a=b与(-2-b)²+(3-b)²=(a+b+3)/2 +2联立,
-1/2a=b与(-2-b)²+(3-b)²=(a+b+3)/2 +2联立,
-1/2 a = b
a = -2 b
代入另一个方程
(-2-b)^2 +(3-b)^2 = (-2b+b+3)/2 + 2
4+4b+b^2 +9 - 6b+b^2 = - 1/2 b + 7/2
2b^2 - 3/2 b + 19/2 = 0
4b^2 - 3b + 19 = 0
Δ
把a=-2b代入第二个方程直接就解出来了啊