(3a-2b)(3a+2b)-(2a-3b)化简1.-x(x-y)+(x-y)(x+xy+y) 化简 2.(x-2xy)x-(9xy-12x的四次方y)÷3xy 3.已知m-0.5m=6求(m+0.5m) 4.试证(2n+1)-1能被8整除(n为自然数) 5.已知a,b,c分别是△ABC的三边,说明:(a+b-c)-4ab<
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![(3a-2b)(3a+2b)-(2a-3b)化简1.-x(x-y)+(x-y)(x+xy+y) 化简 2.(x-2xy)x-(9xy-12x的四次方y)÷3xy 3.已知m-0.5m=6求(m+0.5m) 4.试证(2n+1)-1能被8整除(n为自然数) 5.已知a,b,c分别是△ABC的三边,说明:(a+b-c)-4ab<](/uploads/image/z/5226945-33-5.jpg?t=%EF%BC%883a-2b%29%283a%2B2b%29-%282a-3b%29%E5%8C%96%E7%AE%801.-x%28x-y%29%2B%28x-y%29%28x%2Bxy%2By%EF%BC%89+%E5%8C%96%E7%AE%80+2.%EF%BC%88x-2xy%29x-%289xy-12x%E7%9A%84%E5%9B%9B%E6%AC%A1%E6%96%B9y%EF%BC%89%C3%B73xy+3.%E5%B7%B2%E7%9F%A5m-0.5m%3D6%E6%B1%82%EF%BC%88m%2B0.5m%29+4.%E8%AF%95%E8%AF%81%EF%BC%882n%2B1%29-1%E8%83%BD%E8%A2%AB8%E6%95%B4%E9%99%A4%EF%BC%88n%E4%B8%BA%E8%87%AA%E7%84%B6%E6%95%B0%EF%BC%89+5.%E5%B7%B2%E7%9F%A5a%2Cb%2Cc%E5%88%86%E5%88%AB%E6%98%AF%E2%96%B3ABC%E7%9A%84%E4%B8%89%E8%BE%B9%2C%E8%AF%B4%E6%98%8E%EF%BC%9A%EF%BC%88a%2Bb-c%29-4ab%EF%BC%9C)
(3a-2b)(3a+2b)-(2a-3b)化简1.-x(x-y)+(x-y)(x+xy+y) 化简 2.(x-2xy)x-(9xy-12x的四次方y)÷3xy 3.已知m-0.5m=6求(m+0.5m) 4.试证(2n+1)-1能被8整除(n为自然数) 5.已知a,b,c分别是△ABC的三边,说明:(a+b-c)-4ab<
(3a-2b)(3a+2b)-(2a-3b)
化简1.-x(x-y)+(x-y)(x+xy+y) 化简 2.(x-2xy)x-(9xy-12x的四次方y)÷3xy 3.已知m-0.5m=6求(m+0.5m) 4.试证(2n+1)-1能被8整除(n为自然数) 5.已知a,b,c分别是△ABC的三边,说明:(a+b-c)-4ab<0
(3a-2b)(3a+2b)-(2a-3b)化简1.-x(x-y)+(x-y)(x+xy+y) 化简 2.(x-2xy)x-(9xy-12x的四次方y)÷3xy 3.已知m-0.5m=6求(m+0.5m) 4.试证(2n+1)-1能被8整除(n为自然数) 5.已知a,b,c分别是△ABC的三边,说明:(a+b-c)-4ab<
(3a-2b)(3a+2b)-(2a-3b)=9a-4b-4a+12ab-9b=5a+12ab-13b 1.-x(x-y)+(x-y)(x+xy+y)=-x(x-2xy+y)+x-y=2xy-2y 2、(x-2xy)x-(9xy-12x的四次方y)÷3xy=x-2xy-3xy+4xy 3、m=12 则(m+0.5m) =18 =324 4、(2n+1)-1=4n+4n=4n(n+1) ∵n和n+1是相邻的两个整数,其中必有一个是偶数 ∴4n(n+1)一定是8的倍数 5、(a+b-c)-4ab=(a+b-c-2ab)(a+b-c+2ab)=(a-b+c)(a-b-c)(a+b+c)(a+b-c) ∵a,b,c分别是△ABC的三边,∴a-b+c>0,a-b-c0,a+b-c>0 ∴(a+b-c)-4ab=(a-b+c)(a-b-c)(a+b+c)(a+b-c)