-y³+4y²-4y;2x²-4xy;x²(y²-1)+(1-y²);1/5(x-y)+5(y-x)y²过程,方法教一下,3Q啦、
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/28 11:05:31
![-y³+4y²-4y;2x²-4xy;x²(y²-1)+(1-y²);1/5(x-y)+5(y-x)y²过程,方法教一下,3Q啦、](/uploads/image/z/5221529-17-9.jpg?t=-y%26%23179%3B%2B4y%26%23178%3B-4y%EF%BC%9B2x%26%23178%3B-4xy%EF%BC%9Bx%26%23178%3B%EF%BC%88y%26%23178%3B-1%EF%BC%89%2B%EF%BC%881-y%26%23178%3B%EF%BC%89%EF%BC%9B1%2F5%EF%BC%88x-y%EF%BC%89%2B5%EF%BC%88y-x%EF%BC%89y%26%23178%3B%E8%BF%87%E7%A8%8B%2C%E6%96%B9%E6%B3%95%E6%95%99%E4%B8%80%E4%B8%8B%2C3Q%E5%95%A6%E3%80%81)
-y³+4y²-4y;2x²-4xy;x²(y²-1)+(1-y²);1/5(x-y)+5(y-x)y²过程,方法教一下,3Q啦、
-y³+4y²-4y;2x²-4xy;
x²(y²-1)+(1-y²);1/5(x-y)+5(y-x)y²过程,方法教一下,3Q啦、
-y³+4y²-4y;2x²-4xy;x²(y²-1)+(1-y²);1/5(x-y)+5(y-x)y²过程,方法教一下,3Q啦、
(1)x²(y²-1)+(1-y²)
=x²(y²-1)-(y²-1)
=(y²-1)(x²-1)
=(y+1)(y-1)(x+1)(x-1)
(2)1/5(x-y)+5(y-x)y²
=(x-y)(1/5-5y²)
= 1/5(x-y)(1-25y²)
=1/5(x-y)(1+5y)(1-5y)
两题都是提取公因式,再利用平方差公式展开