因式分解法解下列方程,1.x(x-3)=x 2.x²-6x+9=0 3.2(x+2)²-8=0 4.(2x-5)²-(x+4)²=05.x²+3x=0 6.x²-4x=0
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![因式分解法解下列方程,1.x(x-3)=x 2.x²-6x+9=0 3.2(x+2)²-8=0 4.(2x-5)²-(x+4)²=05.x²+3x=0 6.x²-4x=0](/uploads/image/z/5175847-55-7.jpg?t=%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3%E6%B3%95%E8%A7%A3%E4%B8%8B%E5%88%97%E6%96%B9%E7%A8%8B%2C1.x%EF%BC%88x-3%EF%BC%89%3Dx+2.x%26%23178%3B-6x%2B9%3D0+3.2%EF%BC%88x%2B2%EF%BC%89%26%23178%3B-8%3D0+4.%EF%BC%882x-5%EF%BC%89%26%23178%3B-%EF%BC%88x%2B4%EF%BC%89%26%23178%3B%3D05.x%26%23178%3B%2B3x%3D0+6.x%26%23178%3B-4x%3D0)
因式分解法解下列方程,1.x(x-3)=x 2.x²-6x+9=0 3.2(x+2)²-8=0 4.(2x-5)²-(x+4)²=05.x²+3x=0 6.x²-4x=0
因式分解法解下列方程,
1.x(x-3)=x 2.x²-6x+9=0 3.2(x+2)²-8=0 4.(2x-5)²-(x+4)²=0
5.x²+3x=0 6.x²-4x=0
因式分解法解下列方程,1.x(x-3)=x 2.x²-6x+9=0 3.2(x+2)²-8=0 4.(2x-5)²-(x+4)²=05.x²+3x=0 6.x²-4x=0
1.x(x-3)=x
x(x-3)-x=0
x(x-3-1)=0
x(x-4)=0
x1=0,x2=4
2.x²-6x+9=0
(x-3)²==0
x1=x2=3
3.2(x+2)²-8=0
(x+2)²-4=0
(x+2-2)(x+2+2)=0
x(x+4)=0
x1=0,x2=-4
4.(2x-5)²-(x+4)²=0
(2x-5+x+4)(2x-5-x-4)=0
(3x-1)(x-9)=0
x1=1/3,x2=9
5.x²+3x=0
x(x+3)=0
x1=0,x2=-3
6.x²-4x=0
x(x-4)=0
x1=0,x2=4
1. x(x-3)=x
x(x-3)-x=0
x(x-3-1)=0
x(x-4)=0
x1=0,x2=4
2. x²-6x+9=0
(x-3)²==0
x1=x2=3
3. 2(x+2)²-8=0
(x+2)²-4=0
(x...
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1. x(x-3)=x
x(x-3)-x=0
x(x-3-1)=0
x(x-4)=0
x1=0,x2=4
2. x²-6x+9=0
(x-3)²==0
x1=x2=3
3. 2(x+2)²-8=0
(x+2)²-4=0
(x+2-2)(x+2+2)=0
x(x+4)=0
x1=0,x2=-4
4. (2x-5)²-(x+4)²=0
(2x-5+x+4)(2x-5-x-4)=0
(3x-1)(x-9)=0
x1=1/3,x2=9
5. x²+3x=0
x(x+3)=0
x1=0,x2=-3
6. x²-4x=0
x(x-4)=0
x1=0,x2=4
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