解方程:2(2x+1)²-8(x+1)(x-1)=34
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![解方程:2(2x+1)²-8(x+1)(x-1)=34](/uploads/image/z/474407-71-7.jpg?t=%E8%A7%A3%E6%96%B9%E7%A8%8B%EF%BC%9A2%EF%BC%882x%EF%BC%8B1%EF%BC%89%26%23178%3B%EF%BC%8D8%EF%BC%88x%EF%BC%8B1%EF%BC%89%EF%BC%88x%EF%BC%8D1%EF%BC%89%EF%BC%9D34)
解方程:2(2x+1)²-8(x+1)(x-1)=34
解方程:2(2x+1)²-8(x+1)(x-1)=34
解方程:2(2x+1)²-8(x+1)(x-1)=34
2(2x+1)^2-8(x+1)(x-1)=34
(2x+1)^2-4(x+1)(x-1)=17
4x^2+4x+1- 4(x+1)(x-1)=17
4x^2+4x+1- 4x^2+4=17
4x=12
x=3
左边= 2(2x+1)²-8(x+1)(x-1)
=2(4x^2+4x+1)-8(x^2-1)
=8x+10
则原方程可化为
8x+10=34
8x=24
x=3
解 2(4x^2+4x+1)-8(x^2-1)=34
8x^2+8x+2-8x^2+8=34
8x+10=34
8x=24
x=3