1/x+1/y=2,求2x-xy+2y/3x+5xy+3y的值
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![1/x+1/y=2,求2x-xy+2y/3x+5xy+3y的值](/uploads/image/z/469913-41-3.jpg?t=1%2Fx%2B1%2Fy%3D2%2C%E6%B1%822x-xy%2B2y%2F3x%2B5xy%2B3y%E7%9A%84%E5%80%BC)
1/x+1/y=2,求2x-xy+2y/3x+5xy+3y的值
1/x+1/y=2,求2x-xy+2y/3x+5xy+3y的值
1/x+1/y=2,求2x-xy+2y/3x+5xy+3y的值
1/x+1/y=2,推出x+y=2xy
2x-xy+2y/3x+5xy+3y
=[2(x+y)-xy]/3(x+y)+5xy]
=3xy/11xy=3/11
2x-xy+2y/3x+5xy+3y
=(2/x+2/y-1)/(3/x+3/y+5)
=(4-1)/(6+5)
=3/11