y=a^2+bx+1/4a 当x=1时 函数值为-2 当x=3时其最大值为m 求a=?b=?m=?y=a^2+bx+1/4a =x^2+(b/a)x+1/4a^2x^2+(b/a)x=-1/4a^2x^2+(b/a)x+(b/2a)^2=(-4)a^2+(b/2a)^2(X^2+b/2a)^2= 用的配方法,哪部错了?为什么得不到 a(x+b
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![y=a^2+bx+1/4a 当x=1时 函数值为-2 当x=3时其最大值为m 求a=?b=?m=?y=a^2+bx+1/4a =x^2+(b/a)x+1/4a^2x^2+(b/a)x=-1/4a^2x^2+(b/a)x+(b/2a)^2=(-4)a^2+(b/2a)^2(X^2+b/2a)^2= 用的配方法,哪部错了?为什么得不到 a(x+b](/uploads/image/z/4518114-42-4.jpg?t=y%3Da%5E2%2Bbx%2B1%2F4a+%E5%BD%93x%3D1%E6%97%B6+%E5%87%BD%E6%95%B0%E5%80%BC%E4%B8%BA-2+%E5%BD%93x%3D3%E6%97%B6%E5%85%B6%E6%9C%80%E5%A4%A7%E5%80%BC%E4%B8%BAm+%E6%B1%82a%3D%3Fb%3D%3Fm%3D%3Fy%3Da%5E2%2Bbx%2B1%2F4a+%3Dx%5E2%2B%28b%2Fa%29x%2B1%2F4a%5E2x%5E2%2B%28b%2Fa%29x%3D-1%2F4a%5E2x%5E2%2B%EF%BC%88b%2Fa%29x%2B%EF%BC%88b%2F2a%EF%BC%89%5E2%3D%EF%BC%88-4%EF%BC%89a%5E2%2B%EF%BC%88b%2F2a%EF%BC%89%5E2%EF%BC%88X%5E2%2Bb%2F2a%EF%BC%89%5E2%3D+%E7%94%A8%E7%9A%84%E9%85%8D%E6%96%B9%E6%B3%95%2C%E5%93%AA%E9%83%A8%E9%94%99%E4%BA%86%3F%E4%B8%BA%E4%BB%80%E4%B9%88%E5%BE%97%E4%B8%8D%E5%88%B0+a%EF%BC%88x%2Bb)
y=a^2+bx+1/4a 当x=1时 函数值为-2 当x=3时其最大值为m 求a=?b=?m=?y=a^2+bx+1/4a =x^2+(b/a)x+1/4a^2x^2+(b/a)x=-1/4a^2x^2+(b/a)x+(b/2a)^2=(-4)a^2+(b/2a)^2(X^2+b/2a)^2= 用的配方法,哪部错了?为什么得不到 a(x+b
y=a^2+bx+1/4a 当x=1时 函数值为-2 当x=3时其最大值为m 求a=?b=?m=?
y=a^2+bx+1/4a
=x^2+(b/a)x+1/4a^2
x^2+(b/a)x=-1/4a^2
x^2+(b/a)x+(b/2a)^2=(-4)a^2+(b/2a)^2
(X^2+b/2a)^2=
用的配方法,哪部错了?为什么得不到 a(x+b/2a)^2+(1-b^2/4a)
2,√(π-4)^2=/π-4/(为什么可以化成4-派)
公式n√a^n=丨a丨
y=a^2+bx+1/4a 当x=1时 函数值为-2 当x=3时其最大值为m 求a=?b=?m=?y=a^2+bx+1/4a =x^2+(b/a)x+1/4a^2x^2+(b/a)x=-1/4a^2x^2+(b/a)x+(b/2a)^2=(-4)a^2+(b/2a)^2(X^2+b/2a)^2= 用的配方法,哪部错了?为什么得不到 a(x+b
1
y=ax^2+bx+1/(4a)
=a [x^2+(b/a)x]+1/(4a)
=a[(x^2+(b/a)x+(b/2a)^2-(b/2a)^2]+1/(4a)
=a(X^2+b/2a)^2-a(b/2a)^2+1/(4a)
=a(x+b/2a)^2+(1-b^2)/(4a)
这是对二次函数进行的配方,不是对方程的配方
方程的配方两边可以同时除以一个数,加减一个数,
而函数变形时,只能提取一个数,或加一项减一项
√(π-4)^2=/π-4/
∵ 4-π>0∴|π-4|= 4-π
a. (a>0)
|a|= 0 (a=0)
-a (a